Find the circumference and are of a circle with a diameter of 22 inches. leave answer in terms of pi
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Answer:
See attached diagram
Step-by-step explanation:
You are given the equation of hyperbola
From this equation,
- the center of hyperbola is at point (1,-3);
- the real semi-axes
- the imaginary semi-axes
Draw two parallel lines x=1 and y=-3 (they intersect at the center of hyperbola), then on horizontal line match two hyperbola's vertices (7 units to the left and 7 units to the right from the center). Then draw two branches of hyperbola (one in negative direction and one in positive direction).
Your equation is the following:
11 7/7 - (-8 3/7)
the first step to solving this is to know that when there is a "-" sign in front of the parenthesis, you need to change the sign of each term in the parenthesis.
11 7/7 + 8 3/7
now, add the whole numbers and the fractional parts of the mixed numbers separately.
(11 + 8) + (
)
add the whole numbers together
19 + (
)
now add the fractions together
19 + 10/7
next, convert the improper fraction to a mixed number
19 + 1 3/7
now, you will write the mixed number as a sum of the whole number and its fractional part.
19 + 1 + 3/7
add the numbers together
20 + 3/7
finally, write the sum of the whole number and the fraction as a mixed number
20
let me know if you have any further questions
:)
11 7/7 - (-8 3/7)
the first step to solving this is to know that when there is a "-" sign in front of the parenthesis, you need to change the sign of each term in the parenthesis.
11 7/7 + 8 3/7
now, add the whole numbers and the fractional parts of the mixed numbers separately.
(11 + 8) + (
add the whole numbers together
19 + (
now add the fractions together
19 + 10/7
next, convert the improper fraction to a mixed number
19 + 1 3/7
now, you will write the mixed number as a sum of the whole number and its fractional part.
19 + 1 + 3/7
add the numbers together
20 + 3/7
finally, write the sum of the whole number and the fraction as a mixed number
20
let me know if you have any further questions
:)