Write down in terms of n , an expression for the nth term for this sequence 9 11 13 15 17

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

3 0

Answer:

2n+7

Step-by-step explanation:

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one night a theater sold 548 movie tickets. an adult’s costs $6.50 an child’s cost $3.50. in all, $2,881 was takin in. how many

gavmur [86]

Answer:

321 adult tickets
227 child tickets

Step-by-step explanation:

This sort of problem is easily solved by defining a variable to be the quantity of the higher-value contributor. Here, we can let x represent the number of adult tickets. Then total revenue is ...

6.50x +3.50(548-x) = 2881

3x +1918 = 2881 . . . . . . . . . . . . eliminate parentheses, collect terms

3x = 963 . . . . . . . . . . . . . . . . . . subtract 1918

x = 321 . . . . . . . . . . . . . . . . . . . . divide by 3

548-x = 548 -321 = 227 . . . . . .number of child tickets

321 adult tickets and 227 child tickets were sold.

3 0

3 years ago

A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If

Blababa [14]

Answer: Our required probability is $\dfrac{1}{2}$

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = $\dfrac{1}{3}$

So, Probability of getting head from fair coin = $\dfrac{1}{2}$

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

$\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}$