Direction vector of line of intersection of two planes is the cross product of the normal vectors of the planes, namely
p1: x+y+z=2
p2: x+7y+7z=2
and the corresponding normal vectors are: (equiv. to coeff. of the plane)
n1:<1,1,1>
n2:<1,7,7>
The cross product n1 x n2
vl=
i j l
1 1 1
1 7 7
=<7-7, 1-7, 7-1>
=<0,-6,6>
Simplify by reducing length by a factor of 6
vl=<0,-1,1>
By observing the equations of the two planes, we see that (2,0,0) is a point on the intersection, because this points satisfies both plane equations.
Thus the parametric equation of the line is
L: (2,0,0)+t(0,-1,1)
or
L: x=2, y=-t, z=t
I’ll be happy to help!
Since a right angle is equal to 90 degrees, we can add the 67+90 which equals 157, so since a triangle is equal to 180, we can subtract 180-157.
180-157= 23
The answer for x is 23!
Answer:is (4x-5)
Step-by-step explanation:
Answer:
Step-by-step explanation:
- 9 : 99 = divide both numbers by 9
- 1 : 11
Answer:
X = 18 Y= 30
Step-by-step explanation:
Since you have to do times two to X and Y.
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