The evaluation of the following expressions with groupings are:
<h3>Algebra</h3>
8+ (9-3)
= 8 + (6)
= 14
(8+9)-3
= 17 - 3
= 14
14(10 ÷ 2)
= 14 (5)
= 70
(12-3) - (9.2)
= 9 - 9.2
= -0.2
(4-10) + (75 ÷ 25)
= -6 + (3)
= -6 + 3
= -3
80-3
= 77
8+3
= 11
13+ [2(9- 6)]
= 13 + {2(3)}
= 13 + (6)
= 19
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Answer:
-dx/dy = (1 + x) √(1 − x²)
Step-by-step explanation:
y = √((1 − x) / (1 + x))
Squaring both sides:
y² = (1 − x) / (1 + x)
Take derivative of both sides (use power rule and chain rule on the left, and quotient rule on the right):
2y dy/dx = [(1 + x)(-1) − (1 − x)(1)] / (1 + x)²
2y dy/dx = (-1 − x − 1 + x) / (1 + x)²
2y dy/dx = -2 / (1 + x)²
y dy/dx = -1 / (1 + x)²
Substitute the expression for y:
√((1 − x) / (1 + x)) dy/dx = -1 / (1 + x)²
Multiply both sides by 1 + x:
√((1 − x) (1 + x)) dy/dx = -1 / (1 + x)
√(1 − x²) dy/dx = -1 / (1 + x)
Solve for dy/dx:
dy/dx = -1 / [ (1 + x) √(1 − x²) ]
The gradient of the normal is the slope of the perpendicular line:
-dx/dy = (1 + x) √(1 − x²)
Here's a graph:
desmos.com/calculator/kbglyjdzaj
Answer:
Pounds
Step-by-step explanation:
1 kilogram= about 2.2 pounds
Answer:
![2e^{y'}y=0](https://tex.z-dn.net/?f=2e%5E%7By%27%7Dy%3D0)
Step-by-step explanation:
The solution for this differential equation
have to be the trivial solution y=0. Because the function
always have values different of zero, then the only option is the trivial solution y=0.