Answer: 12 yearly admissions and 38 single admissions
Step-by-step explanation:
Let x be yearly membership
Let y be single admission
x+y=50 --> # of tickets sold
35.25x+6.25y=660.50 --> $ of tickets
Use elimination method to solve (multiply equation 1 by -3525 and equation 2 by 100)
-3525x-3525y=-176250
+ 3525+625y=66050
-----------------------------------
-2900y=-110200
y=38
Substitute y=38 into equation 1
x+38=50
x=12
Therefore, 12 yearly admissions and 38 single admissions were sold
Answer: 18
Step-by-step explanation: 16/2 = 8 - 6 = 2 x 10 = 20 - 2 = 18, sorry if i'm incorrect.
Answer:
(4,3) is the answer
Step-by-step explanation:
Answer:
-56
Step-by-step explanation:
Formula to get determinant is::
![\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20ad-bc)
0(0)-8(7)
0 - 56
-56
Answer:
456 students
Step-by-step explanation:
38% = 0.38
1200 x 0.38 = 456
