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Reptile [31]
3 years ago
8

How have productivity programs improved the professional lives of people? (check all that apply)

Computers and Technology
2 answers:
zhannawk [14.2K]3 years ago
5 0

Answer: 1, 3, 4

  • Made it easier and faster to communicate with others
  • made it easier to manipulate numbers in a spreadsheet
  • made it easier and less expensive to present information

Explanation:

Just took the test on Edge, these are the answers it gave me.

gtnhenbr [62]3 years ago
3 0

Answer:

  • made it easier and less expensive to present information
  • made it easier and faster to communicate with others

Explanation:

productivity programs

productivity programs are designed and use for producing information easily and made it easier and faster to communicate with others

worksheets , charts , graphs , documents etc

MS office , Time management , projects management softwares are the example of  productivity programs

there are alot of tools which are designed to make conversation and communication more easy related to productivity program following are the example of tools

  • Microsoft Teams
  • slack
  • Zoom
  • Office 365
  • Poppulo
  • JIRA Cloud
  • Interact.
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If im downloading a game at 4mb/s how many minutes would it take to download 25 GB
xxMikexx [17]

Answer:

File size  

25  GB  

Connection type Download speed Download time

Modem    28,8 kbit/s                   2071:15:40

Modem     56,6 kbit/s                         1065:13:12

ADSL       256 kbit/s                         233:01:00

ADSL       512 kbit/s                         116:30:30

ADSL       1 Mbit/s                                     59:39:08

ADSL             2 Mbit/s                                     29:49:34

ADSL             8 Mbit/s                                     07:27:23

ADSL             24 Mbit/s                                     02:29:07

LAN             10 Mbit/s                                                 05:57:54

LAN             100 Mbit/s                                     00:35:47

Turbo 3G 7,2 Mbit                           08:17:06

4G             80 Mbit/s                                     00:44:44

Hopefully this helps somewhat

7 0
3 years ago
Read 2 more answers
What is the name of the arm that is attached to the read/write head?
lawyer [7]
This is not making sense?
7 0
3 years ago
Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 3, print "To
SVETLANKA909090 [29]

Answer:

<h2>Function 1:</h2>

#include <stdio.h> //for using input output functions

// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter

void PrintPopcornTime(int bagOunces){

if (bagOunces < 3){ //if value of bagOunces is less than 3

 printf("Too small"); //displays Too small message in output

 printf("\n"); } //prints a new line

//the following else if part will execute when the above IF condition evaluates to //false and the value of bagOunces is greater than 10

else if (bagOunces > 10){

    printf("Too large"); //displays the message:  Too large in output

    printf("\n"); //prints a new line }

/*the following else  part will execute when the above If and else if conditions evaluate to false and the value of bagOunces is neither less than 3 nor greater than 10 */

else {

/* The following three commented statements can be used to store the value of bagOunces * 6 into result variable and then print statement to print the value of result. The other option is to use one print statement printf("%d",bagOunces * 6) instead */

    //int result;

    //result = bagOunces * 6;

    //printf("%d",result);

 printf("%d",bagOunces * 6);  /multiplies value of bagOunces  to 6

 printf(" seconds");

// seconds is followed with the value of bagOunces * 6

 printf("\n"); }} //prints a new line

int main(){ //start of main() function body

int userOunces; //declares integer variable userOunces

scanf("%d", &userOunces); //reads input value of userOunces

PrintPopcornTime(userOunces);

//calls PrintPopcornTime function passing the value in userOunces

return 0; }

Explanation:

<h2>Function 2:  </h2>

#include <stdio.h> //header file to use input output functions

// start of the function PrintShampooInstructions body having integer variable numCycles as parameter

void PrintShampooInstructions(int numCycles){

if(numCycles < 1){

//if conditions checks value of numCycles is less than 1 or not

printf("Too few."); //prints Too few in output if the above condition is true

printf("\n"); } //prints a new line

//else if part is executed when the if condition is false and else if  checks //value of numCycles is greater than 4 or not

else if(numCycles > 4){

//prints Too many in output if the above condition is true

printf("Too many.");

printf("\n"); } //prints a new line

//else part is executed when the if and else if conditions are false

else{

//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done

for(int N = 1; N <= numCycles; N++){

printf("%d",N);

printf(": Lather and rinse. \n");}

printf("Done.");

printf("\n");} }

int main() //start of the main() function body

{    int userCycles; //declares integer variable userCycles

   scanf("%d", &userCycles); //reads the input value into userCycles

   PrintShampooInstructions(userCycles);

//calls PrintShampooInstructions function passing the value in userCycles

   return 0;}

I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN  which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by

printf(": Lather and rinse. \n"); which is followed by printf("Done.");

So at first iteration:

printf("%d",N); prints 1 as the value of N is 1

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

1: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.

Now at second iteration:

The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 2=2. So the program control enters the body of loop.

printf("Done."); prints Done after the above two lines.

printf("%d",N); prints 2 as the value of N is 2

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

2: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.

The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles  which means 3>2. So the loop breaks.

Now the next statement is:

printf("Done."); which prints Done on the screen.

So as a whole the following output is displayed on the screen:

1: Lather and rinse.

2: Lather and rinse.

Done.

The programs along with their outputs are attached.

6 0
3 years ago
Write a loop to print 10 to 90 inclusive (this means it should include both the 10 and 90), 10 per line.​
Masja [62]

Answer:

c = 0

for x in range(10,91):

   print(x, end=" ")

   c = c + 1

   if c>=10:

       print(" ")

       c=0

Explanation:

8 0
3 years ago
Which type of software is the most similar to database software?\
kykrilka [37]
The answer is graphics
5 0
3 years ago
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