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inna [77]
3 years ago
15

I don't understand this​

Mathematics
2 answers:
drek231 [11]3 years ago
6 0
Ok I will help u....

if u have any doubts ask me
please mark as brainliest
aliya0001 [1]3 years ago
3 0

What don’t you understand ?

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This is so confusing D: Please help
just olya [345]
4 treats x=4 yesssssss i think thats it
7 0
3 years ago
Area of a trapizium is 84m².its pararrell sides are 12m and 9m. find its hiegh
Maksim231197 [3]

<em>Answer:</em>

<em>8m</em>

<em>Step-by-step explanation:</em>

<em>We can convert the trapezium into a rectangle to make finding the area easier.</em>

<em>Say that the top side is 9m, and that the bottom side is 12m.</em>

<em>12 - 9 = 3</em>

<em>3/2* = 1.5</em>

<em>*Note that we are dividing by two to get the "overhang" of the bottom side.</em>

<em>Now that we have our overhang, we can find the length of the "t-rect"**.</em>

<em>**"T-rect" refers to a rectangle that has been formed by changing a trapezium into a rectangle.</em>

<em>12 - 1.5 = 10.5</em>

<em>9 + 1.5 = 10.5</em>

<em>The length of the t-rect is 10.5.</em>

<em>84/10.5 = 8</em>

<em>The height of the t-rect is 8m.</em>

<em>Since the height of the original trapezium is equal to the height of the t-rect***, </em>

<em>***Since we have only adjusted the length</em>

<em>this also means that 8m would also be the height of the original trapezium.</em>

<em>Now, there is a second way of doing this.</em>

<em>Find the median of 12 and 9.</em>

<em>9, 10, 11, 12</em>

<em>10, 11</em>

<em>The median is 10.5.</em>

<em>84/10.5 = 8</em>

<em>You get the same answer. These methods could be used as a solve-then-check method to another problem like these.</em>

<em>Hope this helps. Have a nice day.</em>

3 0
3 years ago
A drawer contains quarters and nickels. There are 200 total coins valuing $30.00. Think about a system of equations that can be
Margaret [11]

Answer:

100

Step-by-step explanation:

Let n and q represent the numbers of nickels and quarters, respectively. A suitable system of equations is ...

  n + q = 200 . . . . . . there are 200 coins in the drawer

  5n +25q = 3000 . . .their value is $30.00

For mixture problems like this, it is often a good idea to substitute for the variable representing the contributor of lower value. That is, we want to write an expression for n that we can use for substitution.

Using the first equation to solve for n, ...

  n = 200 - q

Substituting this into the second equation gives ...

  5(200 -q) +25q = 3000

  1000 +20q = 3000 . . . . . . simplify

  20q = 2000 . . . . . . . . . . . . subtract 1000

  q = 100 . . . . . . . . . . . . . . . . divide by 20

  n = 200 -q = 100 . . . . . . . . the number of nickels, as we want

_____

<em>Comment on the solution</em>

We solved for q, then had to do an extra step to find the value of n that the problem asks for. Had we written q = 200-n and used that for substitution, we would have ended with the equation -20n = -2000. This would give the answer for n directly (with no additional steps required).

Sometimes working with negative numbers is uncomfortable or results in errors, so we chose to use the solution method that would avoid negative numbers.

___

<em>Comment on the problem statement</em>

We are told about coins in a <u>drawer</u>, and we are asked about coins in a <u>jar</u>. There is not enough information to answer the question asked. We have had to assume that both refer to the same quantity of coins—an assumption that is not supported by anything in the problem statement.

8 0
3 years ago
Read 2 more answers
What is the 93rd term of the arithmetic sequence -6, 13, 23 and how do I find it?​
e-lub [12.9K]

Answer:

Step-by-step explanation:

the formula for an arithmetic sequence is

a, a+d,a+3d,a+3d etc, where d is the common difference

we have the terms -6, 13,23

first term is -6

-6+19=13

however, 13+10=23

this is not an arithmetic sequence

7 0
2 years ago
V = 1/3 πr^2h<br> Pls help
SpyIntel [72]
Well if we are solving for V then the answer is V= V = πr^2h/3
If your solving for a different letter then tell me. Thanks
5 0
3 years ago
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