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Dmitriy789 [7]
3 years ago
8

What is the critical value for a chi-square test with 13 degrees of freedom at the 1 percent level of significance

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
4 0

Answer: 27.688

Step-by-step explanation:

The critical chi-square value \chi^2_{(df,\alpha)} depends on significance level (\alpha)  and degrees of freedom (df) .

Given significance level: (\alpha) = 1% = 0.01

Degrees of freedom (df)= 13

From the chi-square table, the critical chi-square value for df = 13 and \alpha =0.01

is \chi^2_{(df,\alpha)}=27.688

Hence, the  required critical value = 27.688

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Assume a warehouse operates 24 hours a day. Truck arrivals follow Poisson distribution with a mean rate of 36 per day and servic
kirill [66]

The expected waiting time in system for typical truck is 2 hours.

Step-by-step explanation:

Data Given are as follows.

Truck arrival rate is given by,   α  = 36 / day

Truck operation departure rate is given,   β= 48 / day

A constructed queuing model is such that so that queue lengths and waiting time can be predicted.

In queuing theory, we have to achieve economic balance between number of customers arriving into system and that of leaving the system whether referring to people or things, in correlating such variables as how customers arrive, how service meets their requirements, average service time and extent of variations, and idle time.

This problem is solved by using concept of Single Channel Arrival with exponential service infinite populate model.

Waiting time in system is given by,

w_{s} = \frac{1}{\alpha - \beta  }

        where w_s is waiting time in system

                   \alpha is arrival rate described Poission distribution

                   \beta is service rate described by Exponential distribution

w_{s} = \frac{1}{\alpha - \beta  }

w_{s} = \frac{1}{48 - 36 }

w_{s} = \frac{1}{12 } day

w_{s} = \frac{1}{12 }  \times 24  hour        ...it is due to 1 day = 24 hours

w_{s} = 2 hours

Therefore, time required for waiting in system is 2 hours.

           

                   

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=5x%20-%2010%20%5Cleqslant%2020" id="TexFormula1" title="5x - 10 \leqslant 20" alt="5x - 10 \le
OlgaM077 [116]
The answer is x = 6
Explanation:
First, you must assume that 5x-10=20. Next, you add 10 to 20, which makes the equation 5x=30. Next, divide 30 by 5, which then makes the equation x=6. When you substitute 6 in the original equation, it works, because 5(6)-10 equals 20.
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3 years ago
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Answer:

The first is decay, seeing as it is in between 1 and 0

The second is growth, as it is greater than 1

Step-by-step explanation:

It's exponential growth when the base of our exponential is bigger than 1, which means those numbers get bigger. It's exponential decay when the base of our exponential is in between 1 and 0 and those numbers get smaller.

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3 years ago
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Sergeeva-Olga [200]
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