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2 years ago

9

The playing surfaces of two foosball tables are similar. The ratio of the corresponding side lengths is 10:7 What is the ratio o

f the areas?

1 answer:

mrs_skeptik [129]2 years ago

3 0

100:49 i think.. hope this helps..

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1 and a 1/2 divided by 3/8

Musya8 [376]

$1\frac{1}{2}:\frac{3}{8}=\ \ \ \ | make\ improper\ fractions\\\\
\frac{3}{2}:\frac{3}{8}=\ \ \ \ \ \ | multiply\ first\ factor\ by\ inverse\ of\ the\ second\\\\
\frac{3}{2}*\frac{8}{3}=\frac{3*8}{2*3}=\frac{8}{2}=4$

5 0

2 years ago

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Willy Wonka has 2 candies, Wonka bars and Everlasting Gobstoppers. Both have both natural sugar and sucrose in them. Each Wonka

love history [14]

Answer:

Wonka bars=3 and Everlasting Gobstoppers=24

Step-by-step explanation:

let the wonka bars be X

and everlasting gobstoppers be Y

the objective is to

maximize 1.3x+3.2y=P

subject to constraints

natural sugar

4x+2y=60------1

sucrose

x+3y=75---------2

x>0, y>0

solving 1 and 2 simultaneously we have

4x+2y=60----1

x+3y=75------2

multiply equation 2 by 4 and equation 1 by 1 to eliminate x we have

4x+2y=60

4x+12y=300

-0-10y=-240

10y=240

y=240/10

y=24

put y=24 in equation 2 we have'

x+3y=75

x+3(24)=75

x+72=75

x=75-72

x=3

put x=3 and y=24 in the objective function we have

maximize 1.3x+3.2y=P

1.3(3)+3.2(24)=P

3.9+76.8=P

80.7=P

P=$80.9

8 0

3 years ago

How much longer is a 2 1/2 inch long piece of string than a 2/5 long piece of string

Rashid [163]

It is 2.1 inches longer. Plz plz plz give me brainiest answer I only need 3 more to rank up. If u do I will show my work and show the answer as a fraction.

4 0

2 years ago

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Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

2 years ago

SHAWTY A LIL BXDDIE SHEE LIL MEHHH PUTANGGGG ;) MUHAHAH Imao

daser333 [38]

Answer:

i can agree with that muhahaha

Step-by-step explanation:

8 0

2 years ago

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