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Gala2k [10]
3 years ago
7

In January 2011 the rate of a VAT increased from 17.5% to 20% Work out the difference in price of a car worth £15000 + VAT due t

o the increase of VAT
Mathematics
1 answer:
Jobisdone [24]3 years ago
3 0

Answer:

  £375

Step-by-step explanation:

The tax changed from 17.5% of the car's price to 20% of the car's price, an increase of 2.5% of the car's price.

The increased tax amount is ...

  0.025 × £15000 = £375

The price of the car went up by £375 due to the increase in VAT.

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Jake has decided to invest in three business ventures. The total cost of investing in all three ventures is $15,000. The combine
Arte-miy333 [17]
X = first venture, y = second venture, z = third venture

x + y + z = 15,000
x + z = y + 7000
3x + 2y + 2z = 39,000
these are ur equations.....

x + y + z = 15,000
x - y + z = 7000
--------------------add
2x + 2z = 22,000

x + y + z = 15,000....multiply by -2
3x + 2y + 2z = 39,000
-------------------
-2x - 2y - 2z = - 30,000 (result of multiplying by -2)
3x + 2y + 2z = 39,000
------------------add
x = 9,000

2x + 2z = 22,000
2(9000) + 2z = 22000
18,000 + 2z = 22000
2z = 22000 - 18000
2z = 4000
z = 4000/2
z = 2,000

x + y + z = 15,000
9000 + y + 2000 = 15,000
11,000 + y = 15,000
y = 15,000 - 11,000
y = 4,000

first venture (x) = 9,000 <==
second venture (y) = 4,000 <==
third venture (z) = 2,000 <==
7 0
3 years ago
Read 2 more answers
The number 2 is a factor of _________.
zmey [24]

the number 2 is a factor of all even numbers (b)

5 0
1 year ago
Read 2 more answers
If y varies inversely as x and y=32 when x=3, find x when y=15
deff fn [24]
Y=kx, k is not equal to 0
when y=32,x=3, 32=3k
                           k=32/3
so y=32/3*x
when y=15, 15=32/3*x
                     x=45/32

5 0
3 years ago
Can someone please give me the answers?
kirza4 [7]
Find all the areas and add them together 
Base Rectangle : LxW  = 14 x 12 = 168
Bases Triangles (2)  2x (8x12)/2 = 96
2 Lateral rectangles 14x10 =140 (double) = 280

Surface Area = 168 +96 + 280 = 544

7 0
3 years ago
F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?
SVEN [57.7K]

Answer: -4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

Step-by-step explanation:

Given

Function is F(t)=t^2+19+60

Zeroes of the function are

t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15

Using completing the square method

y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

4 0
3 years ago
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