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N76 [4]
3 years ago
10

Sven got a $150 gift card function A(n) 150 12.30n gives the amount of money left on the gift card after n number of visits to t

he skate park to a local skate park for his birthday. Each trip costs $12.50. The . Find t he x - and y intercepts (or r in this case, n- and Ae) intercepts) and explain what each intercept means in relation to this problem
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
8 0

Answers:

1. The n-intercept is 12. That means after 12 visits the amount of money on the gift car is $0.  

2. The A(n)-intercept is 150. Before the visits, the amount of money on the gift car is $150.


Solution:

Amount of money on the gift card after n number of visits: A(n)=$150-$12.50 n

A(n)=150-12.50 n

1. n-intercept

A(n)=0→150-12.50 n =0

Solving for n: Subtracting 150 both sides of the equation:

150-12.50 n-150 = 0-150

-12.50 n = -150

Dividing both sides of the equation by -12.50:

(-12.50 n) / (-12.50) = (-150) / (-12.50)

n=12

The n-intercept is n=12; for n=12→A(12)=0. Point (n, A(n))=(12,0)


2. A(n) intercept

n=0→A(0)=150-12.50 (0)

A(0)=150-0

A(0)=150

The A(n) intercept is 150; for n=0→A(0)=150. Point (n, A(n))=(0,150)

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7 0
3 years ago
Find the distance between the pair of points. Round your answer to the nearest hundredth. (-8,19) and (3,5)
Amiraneli [1.4K]

Answer:

<h3>The answer is 17.80 units</h3>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-8,19) and (3,5)

The distance between them is

d =  \sqrt{ ({ - 8 - 3})^{2}  +  ({1 9 - 5})^{2} }  \\  =  \sqrt{( { - 11})^{2}  +  {14}^{2} }  \\  =  \sqrt{121 + 196}  \\  =  \sqrt{317}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  = 17.804493...

We have the final answer as

<h3>17.80 units to the nearest hundredth</h3>

Hope this helps you

5 0
3 years ago
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