<h2> (1 ,2) (2,-3)</h2><h2>(x1,y1) (x2, y2)</h2>
<h2> Distance formual</h2>
<h2> √(x2-x1)^+(y2-y1)^</h2>
<h2>= √(2-1)^+(-3-2)^</h2><h2>= √(1)^+(-5)^ [here square root and </h2><h2> square get cancelled]</h2><h2>= (1)+(-5)</h2><h2>= 1-5</h2><h2>= - 4</h2>
Answer:
In the equation of a straight line (when the equation is written as "y = mx + b"), the slope is the number "m" that is multiplied on the x, and "b" is the y-intercept (that is, the point where the line crosses the vertical y-axis). This useful form of the line equation is sensibly named the "slope-intercept form"
Step-by-step explanation:
1. i think 5 to 9
2. i think 3/8
3. 2.24
4. 164+3.28
hope this helps!
Answer:
The length of the segment F'G' is 7.
Step-by-step explanation:
From Linear Algebra we define reflection across the y-axis as follows:
, 
(Eq. 1)
In addition, we get this translation formula from the statement of the problem:
, 
(Eq. 2)
Where:
- Original point, dimensionless.
- Transformed point, dimensionless.
If we know that 
and 
, then we proceed to make all needed operations:
Translation
Reflection
Lastly, we calculate the length of the segment F'G' by Pythagorean Theorem:
![F'G' = \sqrt{(5-5)^{2}+[(-1)-6]^{2}}](https://tex.z-dn.net/?f=F%27G%27%20%3D%20%5Csqrt%7B%285-5%29%5E%7B2%7D%2B%5B%28-1%29-6%5D%5E%7B2%7D%7D)
The length of the segment F'G' is 7.
