The product of the first and third of three consecutive integers is 3 more than 3 times the second integer. Find the integers.
1 answer:
Let:
x = the middle integer
Then the 3 consecutive integers are:
x - 1, x, x + 1
The product of the first and the third integer:
(x - 1)*(x + 1) = x^2 - 1
is equal to:
3 more than 3 times the second integer:
3x + 3
So:
x^2 - 1 = 3x + 3
Solve:
x^2 - 3x - 4 = 0
(x-4)(x+1) = 0
x = -1 and 4
Since x is the middle integer, we have two sets of solutions:
3,4,5 and -2,-1,0
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b(1 -2) i just too the test
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(4,1)
Step-by-step explanation:
let J(6,6) be x1, y1
let K(2,-4) be x2, y2
midpoint = (x1+x2)/2 , (y1+y2)/2
=(6+2)/2 ,(6-4)/2
= 8/2 ,2/2
=4, 1
Answer:
3.25
Step-by-step explanation:
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Answer:
The answer is the option 
Step-by-step explanation:
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-----> by vertical angles
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Answer:
The value of x =10°
Step-by-step explanation:
Check attachment for solution.
Triangle theorem: the sum of the opposite interior angle is equal to the exterior angle.
<JKL+<LJK=<KLM
2x+14+3x+15=7x+9
Collect like terms
2x+3x-7x=9-14-15
-2x=-20
Divide both side by -2
x=10°
