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Arada [10]
3 years ago
13

Csqrt%7B6%7D%20%7D%20%7D%20%7D%20" id="TexFormula1" title=" 3 \sqrt{2 \times 2 \sqrt{8 \times \sqrt{3 \times \sqrt{6} } } } " alt=" 3 \sqrt{2 \times 2 \sqrt{8 \times \sqrt{3 \times \sqrt{6} } } } " align="absmiddle" class="latex-formula">
Help? ​

Mathematics
1 answer:
vazorg [7]3 years ago
4 0
The answer to your question is 12.95

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Multiply (5x^2-6x+2) x (4x^2-3x)
V125BC [204]

Answer:

20x^{4} - 39x^{3} + 26x^{2} - 6x

hope this helps

5 0
2 years ago
Dawson rakes leaves in his neighborhood. The equation y = 10x represents the amount of money he earns. What is the constant of p
Valentin [98]
The constant of proportionality is equal to k in y=kx. In y=10x, the k value is 10.

Final answer: C. 10
3 0
3 years ago
A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer
pshichka [43]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

Z_{o.o5}= -1.648

You reverse the standardization using the formula Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

-1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 7.72ounces

The lower control point will be 7.72 ounces.

The upper value will be:

Z_{0.95}= 1.648

1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 8.28ounces

The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

P(Z≤7.11)- P(Z≤0.70)= 1 - 0.758= 0.242

There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

b. For this item μ= 8.7, the control limits do not change:

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

P(Z≤-2.45)- P(Z≤-5.71)=0.007 - 0= 0.007

There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

5 0
2 years ago
Read 2 more answers
In Lixue’s garden, the green pepper plants grew 5 inches in 34 month. At this rate, how many feet can they grow in one month? (L
beks73 [17]

Answer:

<h2>0.15 inches per month</h2>

Step-by-step explanation:

step one:

This problem is focused on the growth rate of a plant.

given data

the plants grow 5 inches in 34 months

and also that 1 month= 4 weeks

step two:

We can still say that

if 34 months see a growth of 5 inches

then 1 months will be X inches

cross multiply we have

X= 5/32 inches

step three:

converting this number to decimal we have

X= 0.15 inches per month

Therefore the growth rate would be

0.15 inches per month

5 0
3 years ago
Compare and contrast the relative frequency for the whole table in part B with the two-way frequency table given in the activity
PIT_PIT [208]

The way to convert counts into relative frequencies in a Two Way Relative Frequency Table is to divide the count by the total number of items

<h3>What is a Frequency Table?</h3>

This refers to the depiction of the number of times in which an event occurs in the form of a table.

Hence, when a two-way frequency table is used, it shows the visual representation of the possible relationship between different sets of data.

Please note that your question is incomplete as you did not provide the frequency table needed and also the trends and generalizations to find, so a general overview was given.

Read more about frequency tables here:

brainly.com/question/12134864

#SPJ1

3 0
2 years ago
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