<img src="https://tex.z-dn.net/?f=%203%20%5Csqrt%7B2%20%5Ctimes%202%20%5Csqrt%7B8%20%5Ctimes%20%20%5Csqrt%7B3%20%5Ctimes%20%20%5

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3 years ago

Csqrt%7B6%7D%20%7D%20%7D%20%7D%20" id="TexFormula1" title=" 3 \sqrt{2 \times 2 \sqrt{8 \times \sqrt{3 \times \sqrt{6} } } } " alt=" 3 \sqrt{2 \times 2 \sqrt{8 \times \sqrt{3 \times \sqrt{6} } } } " align="absmiddle" class="latex-formula">
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Mathematics

1 answer:

vazorg [7]3 years ago

4 0

The answer to your question is 12.95

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Diego's sister is twice his age minus 9 years. She is also as old as half the sum of the ages of Diego and both of his 12-year-o

slava [35]

Answer:

Diego is 14 years old.

Sister is 19

Step-by-step explanation:

x = Diego's age

x + 24

2x-9 = 2

First to get rid of the fraction we multiply each side by 2

2(2x-9) = 2((x+24)/2)

4x-18 = x+24

The we isolate x

4x-18 = x+24

-x+18 -x+18

3x = 42 Now we divide each side 3

3 3

x = 14

So Diego is 14

Now we can solve for his sister. We can use one of the two equations from earlier to do this.

Plug 14 in for x and then solve for his sister

2(14)-9

28-9

His sister is 19

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3 years ago

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What is 83 x 96 fzoigjwcsvgfmcgksjkvzmclkm

nasty-shy [4]

7968 because you multiply the two numbers to get the final answer

4 0

3 years ago

Solve the equation: 11 = −5x − 2

qwelly [4]

Answer:

x= -13/5

Step-by-step explanation:

3 0

3 years ago

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Help me please:) anyways have a good day

sleet_krkn [62]

The correct answer is option 4! you have a good day as well

6 0

3 years ago

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Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.

Leviafan [203]

Answer:

Option D. 3.73

Step-by-step explanation:

we know that

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

and

$sin^{2}(\alpha)+cos^{2}(\alpha)=1$

step 1

Find cos(X)

we have

$sin(x)=\frac{1}{2}$

we know that

$sin^{2}(x)+cos^{2}(x)=1$

substitute

$(\frac{1}{2})^{2}+cos^{2}(x)=1$

$cos^{2}(x)=1-\frac{1}{4}$

$cos^{2}(x)=\frac{3}{4}$

$cos(x)=\frac{\sqrt{3}}{2}$

step 2

Find tan(x)

$tan(x)=sin(x)/cos(x)$

substitute

$tan(x)=1/\sqrt{3}$

step 3

Find sin(y)

we have

$cos(y)=\frac{\sqrt{2}}{2}$

we know that

$sin^{2}(y)+cos^{2}(y)=1$

substitute

$sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(y)=1-\frac{2}{4}$

$sin^{2}(y)=\frac{2}{4}$

$sin(y)=\frac{\sqrt{2}}{2}$

step 4

Find tan(y)

$tan(y)=sin(y)/cos(y)$

substitute

$tan(y)=1$

step 5

Find tan(x+y)

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

substitute

$tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73$

7 0

3 years ago