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3 years ago

Csqrt%7B6%7D%20%7D%20%7D%20%7D%20" id="TexFormula1" title=" 3 \sqrt{2 \times 2 \sqrt{8 \times \sqrt{3 \times \sqrt{6} } } } " alt=" 3 \sqrt{2 \times 2 \sqrt{8 \times \sqrt{3 \times \sqrt{6} } } } " align="absmiddle" class="latex-formula">
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Mathematics

1 answer:

vazorg [7]3 years ago

4 0

The answer to your question is 12.95

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8x – 3 = -19<br><br>Who give it fast they have branliest <br>Give the correct answer step by step

lakkis [162]

Answer:

Step-by-step explanation:

$8x - 3 = - 19$

Collect like terms and simplify

$8x = - 19 + 3 \\ 8x = - 16$

Divide both sides of the equation by 8

$\frac{8x}{8} = \frac{ - 16}{8}$

Simplify

$x = - 2$

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%282%20-%206x%29%20-%204%28x%20%20%2B%20%20%5Cfrac%7B3%7D%7B2%7D%29%20

Art [367]

Answer:

x=-2

Step-by-step explanation:

1/2(2-6x)-4(x+3/2)=-(x-3)+4

(1-3x)-4x-6=-x+3+4

-7x-5=-x+7

Tranpose

-7x+x=5+7

-6x=12

Divide by -6

x=-2

4 0

3 years ago

Choose a reasonable estimate. The height of your kitchen table: 68 cm ? 68m

Mademuasel [1]

Answer:

68 cm, 68 m is too big.

Step-by-step explanation:

8 0

2 years ago

How do you do this question?

katovenus [111]

<h3>4 Answers: A, C, E, and F</h3>

================================================

Explanation:

Choice A is true assuming we have $a_n = (-1)^n*b_n$

In this case, $a_n = (-1)^n*\frac{1}{\sqrt{n}}$ and $b_n = \frac{1}{\sqrt{n}}$

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Choice B is false. See choice A above.

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Choice C is true. The sequence $\{b_n\}$ is decreasing. As n gets larger, $b_n$ gets smaller. This is because the denominator is growing larger with the numerator held constant.

--------

Choice D is false. This contradicts choice C.

--------

Choice E is true since the denominator is growing forever

This is similar to $\displaystyle \lim_{n \to \infty} \frac{1}{n} = 0$

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Choice F is true due to choices C and E being true.

--------

Choice G is false because it contradicts choice F.

8 0

3 years ago

Let x1, x2, and x3 represent the times necessary to perform three successive repair tasks at a certain service facility. suppose

kirza4 [7]

Answer:

P(T₀ < 200) = 0.99856

P(150 < T₀ < 200) = 0.99856

Step-by-step explanation:

The expected values for each of the tasks is μ₁ = 60, μ₂ = 60, μ₃ = 60

The variances for each of the 3 tasks

σ₁² = 15, σ₂² = 15, σ₃² = 15

calculate P(T₀ < 200) and P(150 < T₀ < 200)

When independent distributions are combined, the combined mean and combined variance are given through the relation

Combined mean = Σ λᵢμᵢ

(summing all of the distributions in the manner that they are combined)

Combined variance = Σ λᵢ²σᵢ²

(summing all of the distributions in the manner that they are combined)

Distribution of total time taken for the 3 successive tasks

= X₁ + X₂ + X₃

Expected value = Combined Mean = μ₁ + μ₂ + μ₃ = 60 + 60 + 60 = 180

Combined Variance = 1²σ₁² + 1²σ₂² + 1²σ₃²

= (1² × 15) + (1² × 15) + (1² × 15)

= 45

standard deviation of the combined distribution = √(variance) = √45 = 6.708

Since each of the distributions are said to be normal, the combined distribution too, is normal.

P(T₀ < 200)

We first standardize 200

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (200 - 180)/6.708 = 2.98

The required probability

= P(T₀ < 200) = P(z < 2.98)

We'll use data from the normal probability table for these probabilities

P(T₀ < 200) = P(z < 2.98) = 0.99856

b) P(150 < T₀ < 200)

We first standardize 150 and 200

For 150

z = (x - μ)/σ = (150 - 180)/6.708 = -4.47

For 200

z = (x - μ)/σ = (200 - 180)/6.708 = 2.98

The required probability

= P(150 < T₀ < 200) = P(-4.47 < T₀ < 2.98)

We'll use data from the normal probability table for these probabilities

P(150 < T₀ < 200) = P(-4.47 < T₀ < 2.98)

= P(z < 2.98) - P(z < -4.47)

= 0.99856 - 0.0000 = 0.99856

Hope this Helps!!!

6 0

3 years ago