Write regular expressions for the following languages:
1 answer:
Answer:
a) ^.{9}[0][0-1]*$
b) (?=.*^[0-1]*$)(?=.*^(?!.*00(.*00))).*
Explanation:
You can check the expression with the code in python, please see the image with the expressions evaluated for different cases.
a) First, we check if the position number 10 contains a zero by using the expression .{9}[0] and then we check that the input contains just numbers from zero to one (binary numbers) by using [0-1]
b) To understand this expression we need to know that ?=.* helps us evaluate two different expression and if one of the two is false the result is false (and gate), the first expression to be evaluated is [0-1] an it checks that the input contains just numbers from zero to one, the second expression 00(.*00) checks that there is not more than one pair of zeros.
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Answer:
Explanation:
The following code was written in Java and modifies the code so that for the given input such as 3 it outputs the exact information shown in the sample output.
import java.util.Scanner;
class CallPersonInfo {
public static void main(String [] args) {
Scanner scnr = new Scanner(System.in);
PersonInfo person1 = new PersonInfo();
int personsKid;
System.out.println("How many kids do you have:");
personsKid = scnr.nextInt();
person1.setNumKids(personsKid);
/* Your solution goes here */
System.out.println("Kids: " + person1.getNumKids());
person1.incNumKids();
System.out.println("New Baby, kids now: " + person1.getNumKids());
}
}
class PersonInfo {
private int numKids;
public void setNumKids(int setPersonsKids) {
numKids = setPersonsKids;
}
public void incNumKids() {
numKids = numKids + 1;
}
public int getNumKids() {
return numKids;
}
}
