If a baseball is projected upward from ground level with an initial velocity of 64 feet per second, then it’s height is a functi
on of time, given by s= -16t^2+64t. What is the maximum height reached by the ball?
2 answers:
Answer:
64 ft
Step-by-step explanation:
The equation can be factored as ...
s = -16t(t -4)
This is the equation of a downward-opening parabola with t-intercepts of 0 and 4. The maximum height is at the vertex, halfway between those values, at t=2. At that time, the height is ...
s = -16(2)(2-4) = 64 . . . . feet
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