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Vanyuwa [196]
4 years ago
10

If a baseball is projected upward from ground level with an initial velocity of 64 feet per second, then it’s height is a functi

on of time, given by s= -16t^2+64t. What is the maximum height reached by the ball?

Mathematics
2 answers:
cupoosta [38]4 years ago
6 0

Answer:

  64 ft

Step-by-step explanation:

The equation can be factored as ...

  s = -16t(t -4)

This is the equation of a downward-opening parabola with t-intercepts of 0 and 4. The maximum height is at the vertex, halfway between those values, at t=2. At that time, the height is ...

  s = -16(2)(2-4) = 64 . . . . feet

Tatiana [17]4 years ago
4 0

Answer:

Step-by-step explanation:

Try to Google it it will work better than this

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Answer: area of the path alone is 178.98 ft²

Step-by-step explanation:

Since the circular garden is surrounded by a circular path, two circles are formed.

The formula for determining the area of a circle is expressed as

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Where

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Considering the circular garden,

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Area = 3.14 × 11² = 379.94 ft²

Area of the path alone is the circular garden and the circular path together - area of circular path

It becomes

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