If a baseball is projected upward from ground level with an initial velocity of 64 feet per second, then it’s height is a functi
on of time, given by s= -16t^2+64t. What is the maximum height reached by the ball?
2 answers:
Answer:
64 ft
Step-by-step explanation:
The equation can be factored as ...
s = -16t(t -4)
This is the equation of a downward-opening parabola with t-intercepts of 0 and 4. The maximum height is at the vertex, halfway between those values, at t=2. At that time, the height is ...
s = -16(2)(2-4) = 64 . . . . feet
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Answer:
x = 67.50 ft
Step-by-step explanation:
Consider, ΔMAB and ΔMNP,
∠M = ∠M (Common)
Given AB║NP and let MN as transversal,
∠MAB = ∠MNP (alternate angle)
Also, Given AB║NP and let MP as transversal,
∠MBA = ∠MPN (alternate angle)
Therefore, ΔMAB ≅ ΔMNP (By AAA similarity )
Thus, by CPCT,
consider first two ratios,
Substitute the values, MA = MN - AN = 49.5 ft
On solving for x , we get, x = 67.50 ft
Thus, value of x is 67.50 ft
Answer:
- 3x² is a term in the numerator
- x + 1 is a common factor
- The denominator has 3 terms
Step-by-step explanation:
You can identify terms and count them before you start factoring. Doing so will identify 3x² as a term in the numerator, and will show you there are 3 terms in the denominator.
When you factor the expression, you get ...
This reveals a common factor of x+1.
So, the above three observations are true of this rational expression.