The length of the transverse axis is 6,and the length of the red line segment is 15,.how long is the blue line segment?
1 answer:
Answer:
The length of blue segment is:
9
Step-by-step explanation:
We know that the:
Length of transverse axis i.e. '2a' is equal to 6.
i.e. 2a=6.
Also the distance of a point from one focus is 15.
and let the length of the blue segment be 'b'.
<em>" As we know that the absolute value of the difference of distance of a point from the two focus is equal to the length of a transverse axis "</em>
<em>Hence,</em>
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Hence, we have:
Hence, the length of the blue segment is:
9
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Solving this question will involve basic division knowledge.
<em><u>The different positive integer values of n are; 4,6,8,12,24</u></em>
From knowledge on division, we know that when 27 is divided by N and we have 3 as remainder, we can express it as;
= quotient +
Now let us rearrange to get;
-
= quotient
this gives;
= quotient
Now to get how many positive integers can be n, it means all positive values of the quotient must be positive integers as well.
Factors of 24 are; 1, 2, 3, 4, 6, 8, 12, 24
Thus, the possible positive integers will come from this list.
But we can't make use of 1,2,3 as possible values of n because when we divide with 27, we will get either an exact value or 1 as the remainder.
Thus <em>the possible positive integer values of n are; 4,6,8,12,24</em>
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Read more at; brainly.in/question/20088076
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