Answer:
v increases when u increases
Step-by-step explanation:
From the question, we have that
![v = u - \frac{1}{3} * 3](https://tex.z-dn.net/?f=v%20%3D%20u%20-%20%5Cfrac%7B1%7D%7B3%7D%20%2A%203)
![v = u - \frac{3}{3}](https://tex.z-dn.net/?f=v%20%3D%20u%20-%20%5Cfrac%7B3%7D%7B3%7D)
![v = u - 1](https://tex.z-dn.net/?f=v%20%3D%20u%20-%201)
Take u = 1
![v = u - 1](https://tex.z-dn.net/?f=v%20%3D%20u%20-%201)
![v = 1 - 1](https://tex.z-dn.net/?f=v%20%3D%201%20-%201)
![v = 0](https://tex.z-dn.net/?f=v%20%3D%200)
Take u = 2
![v = u - 1](https://tex.z-dn.net/?f=v%20%3D%20u%20-%201)
![v = 2 - 1](https://tex.z-dn.net/?f=v%20%3D%202%20-%201)
![v = 1](https://tex.z-dn.net/?f=v%20%3D%201)
Take u = 10
![v = u - 1](https://tex.z-dn.net/?f=v%20%3D%20u%20-%201)
![v = 10 - 1](https://tex.z-dn.net/?f=v%20%3D%2010%20-%201)
![v = 9](https://tex.z-dn.net/?f=v%20%3D%209)
<em>This implies that an increment in u brings an increment in v</em>
Answer:
1 224
Step-by-step explanation:
A^2 + b^2=c^2
So do 30 ^2 and 18^2
And add both
The formula for finding the volume of a cone is V = 1/3 x pi x r^2 x h. Using the information given, you would have the following problem to calculate: 1/3 x 3.14 6 x 6 x 18. The volume is approximately 678.24 cubic cm or 216 pi cm^3. You would give you answer as V = 216 pi cm^3.
Answer:
Check the explanation
Step-by-step explanation:
One way ANOVA
The null and alternative hypothesis for this one way ANOVA is given as below:
Null hypothesis: H0: There is no significant difference in the averages of the scores for the quizzes, exams and final only.
Alternative hypothesis: There is a significance difference in the averages of the scores for the quizzes, exams and final only.
The ANOVA table with calculations can be seen in the attached images below:
In the attached image below, we get the p-value for this one way ANOVA test as 0.0221. We do not reject the null hypothesis if the p-value is greater than the given level of significance and we reject the null hypothesis if the p-value is less than the given level of significance or alpha value.
In the attached image below, we are given that the p-value = 0.0221 and level of significance or alpha value = 0.05, that is p-value is less than the given level of significance. So, we reject the null hypothesis that there is no significant difference in the averages of the scores for the quizzes, exams and final only. This means we conclude that there is a significance difference in the averages of the scores for the quizzes, exams and final only.