x^2 + y^2 + 2x - 6y + 1 = 0
x^2 +2x + 1 + y^2 - 6y = 0
x^2 + 2( x × 1) + 1^2 + y^2 - 2(y×3) + 3^2 -3^2 =0
(x+1)^2 + (y-3)^2 = 3^2
comparing with circle equation
(x-a)^2 + (y - b)^2 = r^2
where (a , b) is centre of circle.
so we get center of circle is
(-1, 3)
Solve for y by simplifying both sides of the inequality, then isolating the variable.
Inequality Form:
y<−10 or 1<y<6
Interval Notation:
(−∞,−10)∪(1,6)
Answer:
A
Step-by-step explanation:
first lets find the area of the square
A=l*w
12*12=144 m^2
then lets find the are of the circle
A=pi*r^2
A=3.14*(d/2)^2
the diameter of the circle is 12m
A=3.14*(12/2)^2
A=3.14*(6)^2
A=3.14*36
A=113.04 m^2
Now, lets subtract the area of the circle form the area of the square
144-113.04= 30.96 m^2
So, the answer is A
Answer:-2
Step-by-step explanation:
whatever the number attachted to x is, is the slope
8.75 + 0.50 =9.25 dollars spend but she has 16 dollars so 16 - 9.25 = 6.75 dollars left