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I am Lyosha [343]
3 years ago
12

The top of the rectangular box is 15 cm by 20 cm and its hight is 4 cm. And ant begins at one corner of the box and walks along

the edges. It touches all 8 corners what is the shortest distance in cm that the ant may travel

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
8 0

Answer:

92 cm

Step-by-step explanation:

Look at the attached photo, it may give you a better understanding

As we know it touches all 8 corners so the shortest distance in cm that the ant may travel is:

15+ 4+15+4 +20 + 15 +15 + 4 = 92 cm

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Write an equivalent expression of 8m-(5+2m) without parentheses​
Kipish [7]

Answer:

6m-5

Step-by-step explanation:

first you have distribute the negative to the equation in the parentheses so you get

8m - 5 - 2m

Then combine the like terms

So the final answer is 6m-5

6 0
3 years ago
Please help i don't know what I'm doing!!! :( multiply and simplify cot x( sin x - sec x)
fgiga [73]

Answer:

  cos(x) -csc(x)

Step-by-step explanation:

It is helpful to know the relations between the trig functions:

  \cot{x}=\dfrac{\cos{x}}{\sin{x}}\\\\\sec{x}=\dfrac{1}{\cos{x}}\\\\\csc{x}=\dfrac{1}{\sin{x}}

__

Then the given expression can be simplified as follows:

  \cot{x}(\sin{x}-\sec{x})=\dfrac{\cos{x}}{\sin{x}}\left(\sin{x}-\dfrac{1}{\cos{x}}\right)=\cos{x}-\dfrac{1}{\sin{x}}\\\\=\boxed{\cos{x}-\csc{x}}

6 0
3 years ago
find the consecutive even integers such that three times the larger number is 30 more than the smaller one. help :')
Minchanka [31]

Answer:

12 and 14

Step-by-step explanation:

Let the even integers be x and x+2

three times the larger number is expressed as 3(x+2)

30 more than the smaller one is x + 30

Equating both expressions

3(x+2) = x +30

Find x

3x+6 = x+30

3x-x = 30-6

2x = 24

x = 12

The second integer is 12+2 = 14

Hence the required integers are 12 and 14

4 0
3 years ago
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