<h3>
Answer: B. 40</h3>
For any triangle, the three angles always add to 180
(y+10)+(2y)+(50) = 180
3y+60 = 180 ... combine like terms
3y+60-60 = 180-60 ... subtract 60 from both sides
3y = 120
3y/3 = 120/3 .... divide both sides by 3
y = 40
X= 5x Y=-6 I just added them together
<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
Answer:
Step-by-step explanation:
35+12*x ; where x = amount of months
yuhhh get into ittttttt luv