3 years ago

Convert 7.6 cm/yr (centimeters per year) to km/Myr (kilometer per million years.

1 answer:

4 0

You'd do the same as in brainly.com/question/2700999

lemme hmmm redo the fractions... and as I said, you flip them around as needed
$\cfrac{7.6cm}{1y}\cdot \cfrac{1m}{100cm}\cdot \cfrac{1km}{1000m}\cdot \cfrac{1,000,000y}{1myr}$

notice, we flipped them some, so the unit ends either above or below
in order to cancel the one on the left

You might be interested in

Find an expression which represents the difference when (-2x+10y) is subtracted from (5x−7y) in simplest terms.

Zepler [3.9K]

Answer:

7x-17y

Step-by-step explanation:

We need to find the expression which represents the difference when (-2x+10y) is subtracted from (5x−7y) . Let the result is R.

So,

R = (5x−7y)-(-2x+10y)

Solving brackets as follows :

R = (5x−7y)+2x-10y

taking like terms together

R = (5x+2x)+(-7y-10y)

R = 7x-17y

Hence, when (-2x+10y) is subtracted from (5x−7y) the result is (7x-17y).

5 0

3 years ago

Plz help, I don't get it

amm1812

Step-by-step explanation:

$(a+b)^{2} =a^{2} +2ab+b^{2}$

e.g.

$(x+9)^{2} =x^2+2(x)(9)+81$

$(x+9)^{2} =x^2+18x+81$

8 0

3 years ago

Michael finds that 35 customers at his grandfather's grocery store use a coupon. To simulate the behavior of the next 5 customer

denis-greek [22]

6/15 trials had 4 or more coupon customers.
6/15=40%
There is a 4/10 shot of pulling 4 or more coupon customers

7 0

3 years ago

A farmer needs to drive from his farm into town to pick up supplies. He usually drives 29 miles on a straight stretch of highway

Nadya [2.5K]

We are given with
29 miles distance in a straight travel
21 miles up to an intersection, if the farmer has to travel 5 miles to the right, then 10 miles left and 5 miles left, the total distance would be 41 miles
The difference in the distance is 41 miles - 29 miles = 12 miles<span />

5 0

3 years ago

Read 2 more answers

Emma wanted to make an origami fish for each of her 22 classmates. It takes 30 minutes to make one fish. how long will it take E

enot [183]

Hdjdhgg de hdjdhfhgfgggb

7 0

3 years ago