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3 years ago

Which one of the following software packages is most suitable for professional desktop publishers?

1 answer:

5 0

Assuming you mean this
<span>A. Broderbund Printshop </span>
<span>B. Corel Printhouse </span>
<span>C. Adobe PageMaker </span>
<span>D. Microsoft Windows
</span>From a google search
It really comes down to preference. One that our marketing group uses is Quark, which is another one to add to your list. Out of those you listed, I'd recommend PageMaker, which can produce very professional results if you know what you're doing.

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Data Structure in C++

agasfer [191]

The code .cpp is available bellow

#include<iostream>

using namespace std;

//declaring variables

void merge(int* ip, int sz, int* opt, bool opt_asc); //merging

int* mergesort(int* ip, int sz);

void mergesort(int *ip, int sz, int* opt, bool opt_asc);

void merge(int* ip, int sz, int* opt, bool opt_asc)

{

int s1 = 0;

int mid_sz = sz / 2;

int s2 = mid_sz;

int e2 = sz;

int s3 = 0;

int end3 = sz;

int i, j;

if (opt_asc==true)

{

i = s1;

j = e2 - 1;

while (i < mid_sz && j >= s2)

{

if (*(ip + i) > *(ip + j))

{

*(opt + s3) = *(ip + j);

s3++;

j--;

}

else if (*(ip + i) <= *(ip + j))

{

*(opt + s3) = *(ip + i);

s3++;

i++;

}

if (i != mid_sz)

{

while (i < mid_sz)

{

*(opt + s3) = *(ip + i);

s3++;

i++;

}

if (j >= s2)

{

while (j >= s2)

{

*(opt + s3) = *(ip + j);

s3++;

j--;

}

else

{

i = mid_sz - 1;

j = s2;

while (i >= s1 && j <e2)

{

if (*(ip + i) > *(ip + j))

{

*(opt + s3) = *(ip + i);

s3++;

i--;

}

else if (*(ip + i) <= *(ip + j))

{

*(opt + s3) = *(ip + j);

s3++;

j++;

}

if (i >= s1)

{

while (i >= s1)

{

*(opt + s3) = *(ip + i);

s3++;

i--;

}

if (j != e2)

{

while (j < e2)

{

*(opt + s3) = *(ip + j);

s3++;

j++;

}

for (i = 0; i < sz; i++)

*(ip + i) = *(opt + i);

}

int* mergesort(int* ip, int sz)

{

int* opt = new int[sz];

mergesort(ip, sz, opt, true);

return opt;

}

void mergesort(int *ip, int sz, int* opt, bool opt_asc)

{

if (sz > 1)

{

int q = sz / 2;

mergesort(ip, sz / 2, opt, true);

mergesort(ip + sz / 2, sz - sz / 2, opt + sz / 2, false);

merge(ip, sz, opt, opt_asc);

}

int main()

{

int arr1[12] = { 5, 6, 9, 8,25,36, 3, 2, 5, 16, 87, 12 };

int arr2[14] = { 2, 3, 4, 5, 1, 20,15,30, 2, 3, 4, 6, 9,12 };

int arr3[10] = { 10, 9, 8, 7, 6, 5, 4, 3, 2, 1 };

int *opt;

cout << "Arays after sorting:\n";

cout << "Array 1 : ";

opt = mergesort(arr1, 12);

for (int i = 0; i < 12; i++)

cout << opt[i] << " ";

cout << endl;

cout << "Array 2 : ";

opt = mergesort(arr2, 14);

for (int i = 0; i < 14; i++)

cout << opt[i] << " ";

cout << endl;

cout << "Array 3 : ";

opt = mergesort(arr3, 10);

for (int i = 0; i < 10; i++)

cout << opt[i] << " ";

cout << endl;

return 0;

}

4 0

4 years ago

Using a loop and indexed addressing, write code that rotates the members of a 32-bit integer array forward one position. The val

My name is Ann [436]

<h2>Answer:</h2><h2></h2>

//begin class definition

public class Rotator{

//main method to execute the program

public static void main(String []args){

//create and initialize an array with hypothetical values

int [] arr = {10, 20, 30, 40};

//create a new array that will hold the rotated values

//it should have the same length as the original array

int [] new_arr = new int[arr.length];

//loop through the original array up until the

//penultimate value which is given by 'arr.length - 1'

for(int i = 0; i < arr.length - 1; i++ ){

//at each cycle, put the element of the

//original array into the new array

//one index higher than its index in the

//original array.

new_arr[i + 1] = arr[i];

}

//Now put the last element of the original array

//into the zeroth index of the new array

new_arr[0] = arr[arr.length - 1];

//print out the new array in a nice format

System.out.print("[ ");

for(int j = 0; j < new_arr.length; j++){

System.out.print(new_arr[j] + " ");

}

System.out.print("]");

}

<h2>Sample Output:</h2>

[ 40 10 20 30 ]

<h2>Explanation:</h2>

The code above is written in Java. It contains comments explaining important parts of the code. A sample output has also been provided.

7 0

3 years ago

What is the intellectual property

Ede4ka [16]

Answer:

B- intangible ideas

Explanation:

The B. intangible ideas are the correct option certainly. By intangible items we mean Ideas, knowledge, talent, data, trade secret, and intellectual property is also a part of it like the trademarks, patents, and copyrights. And hence intellectual property is a kind of the B. intangible idea. Thus, B is the correct option.

7 0

4 years ago

How to mark someone's answer brainiest?

saul85 [17]

there has to be more than one answer, then click mark as the brainiest

6 0

3 years ago

A field with the ____ data type stores a unique value generated by Access for each record. It usually starts with 1, and Access

natka813 [3]

Answer:

autonumber data type

6 0

2 years ago