2 years ago

What is the answer to 23(15-5+3)44-6

Mathematics

1 answer:

Andreas93 [3]2 years ago

3 0

hope it helps u..........

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Write and solve an equation to find the value of x and a missing angle in the triangle below.

Arturiano [62]

Answer:

x = 27°, ∠JLK = 55°

Step-by-step explanation:

From the diagram in the question above,

The exterior angle of a triangle is equal to the sum of the two opposite side

3x+13 = 39+(2x+1)

3x+13 = 40+2x

collect like terms and solve for x

3x-2x = 40-13

x = 27°.

∠JKL = 2x+1

Substitute the value of x

∠JKL = 2(27)+1

∠JKL = 54+1

∠JKL = 55°

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2 years ago

Suppose you are given two angles A and B in which angle a is equal to angle b. If the measure of a compliment of angle a is equa

zepelin [54]

5x + 20 = 90 - a = 90 - (3x + 40)
5x + 20 = 90 - 3x - 40 = 50 - 3x
5x + 3x = 50 - 20
8x = 30
x = 30/8 = 15/4

b = 3(15/4) + 40 = 45/4 + 40 = 51.25
The measure of a supplementary angle is 180 - 51.25 = 128.75

4 0

3 years ago

Can y’all please help?

alex41 [277]

Answer:

Step-by-step explanation:

You subtract 220 - 129 = 91 then divide by 13

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2 years ago

Evaluate mathematical problem for one by two<br><img src="https://tex.z-dn.net/?f=%201000%20%20%5Ctimes%2010" id="TexFormula1" t

svp [43]

1000*10

Multiply values together

10000

7 0

1 year ago

Read 2 more answers

What would the variables for a and b be? 3/x + 5/x^2 = (ax+b)/x^2

allsm [11]

Answer:

a=3,b=5

Step-by-step explanation:

$\frac{3}{x} + \frac{5}{ {x}^{2} } \\ = \frac{3x}{ {x}^{2} } + \frac{5}{ {x}^{2} } \\ = \frac{3x + 5}{ {x}^{2} }$

so as you got it:

$\frac{(ax + b)}{ {x}^{2} } = \frac{3x + 5}{ {x}^{2} } \\ a = 3 \\ b = 5$

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2 years ago

What is the answer to 2*3(15-5+3)4*4-6

What is the answer to 23(15-5+3)44-6