2 1/2 5n what does n equal

Jack wants to buy a pair of trousers for $60. When he went to the store he found that the price was marked down by 20%. How much

Snowcat [4.5K]

The trousers will cost $48.

60 / 100 = 0.6

20% off so that will make it 80% of 60 so you put the two together by doing:

0.6 * 80 = 48

3 0

3 years ago

Sung Lee invests $10,000 at age 18. He hopes the investment will be worth $30,000 when he turns 25. If the interest compounds co

zalisa [80]

Answer:

r=17%

Step-by-step explanation:

P is the investment

A is the targeted amount

t= time (25-18=7 years)

A=P(1+r)^t

30000=10000(1+r)^7

(1+r)^7=30000/10000

r=\root(7)(3)-1

r=0.16993 ≅0.17= 17%

check: A=P(1+r)^t ⇒10000(1+0.17)^7=30012≅30000

3 0

3 years ago

#11 (Angles with Equations) In the figure below, 2POR is 180°.

lina2011 [118]

Answer:

55

Step-by-step explanation:

The three angles form a straight line, so they add to 180.

x + x + 70 = 180

Combine like terms

2x+70 =180

Subtract 70 from each side

2x+70-70 =180-70

2x= 110

Divide by 2

x = 55

SQT = x

So SQT = 55

4 0

3 years ago

I need to get brain list

goldfiish [28.3K]

Answer:

what it do 5v

Step-by-step explanation:

5 0

4 years ago

A fast food restaurant executive wishes to know how many fast food meals adults eat each week. They want to construct a 98% conf

adelina 88 [10]

Answer:

$n=(\frac{2.326(1.1)}{0.07})^2 =1336.006 \approx 1337$

So the answer for this case would be n=1337 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=1.1$ represent the population standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =0.07 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And in excel we can use this formula to find it:"=-NORM.INV(0.01;0;1)", and we got $z_{\alpha/2}=2.326$ , replacing into formula (b) we got:

$n=(\frac{2.326(1.1)}{0.07})^2 =1336.006 \approx 1337$

So the answer for this case would be n=1337 rounded up to the nearest integer

3 0

4 years ago