Ask question

Ask question

All categories

3 years ago

14

Reynaldo rode his bike 2 miles north and 3 miles east. Which equation should he use to find the distance, d, that takes him dire

ctly back home?
A triangle has side lengths 2, 3, and hypotenuse d.
2 squared + 3 squared = d squared
3 squared minus 2 squared = d squared
d squared + 2 squared = 3 squared
d squared + 3 squared = 2 squared

1 answer:

kotykmax [81]3 years ago

7 0

Answer:

The first one, 2 square+ 3 squared= <em>d </em>squared

Step-by-step explanation:

The theory for finding the hypotenuse of a triangle is:

$a^{2} + b^{2} = c^{2}\\or\\(2)^{2}+(3)^{2}=d^{2}$

You might be interested in

Which of the following statements about Pascal’s Triangle are true? It is symmetrical. The first diagonal is all 1’s. The second

d1i1m1o1n [39]

Answer: The following statements are true:

It is symmetrical.

The first diagonal is all 1’s.

The second diagonal is the counting numbers.

Any number in the triangle is the sum of the two numbers directly above it.

Each row adds to a power of 2.

8 0

3 years ago

PLEASE HEP ASAP!!!!!!! 30 POINTS!!!!!

anzhelika [568]

Answer:

a) 42°F < x < 176°F

b) The inequality graph is attached.

c) No, This is because at 20° F benzene would not be in liquid form but in solid form.

Step-by-step explanation:

According to the Question,

a) For the benzene to remain in liquid form, the temperature of benzene must be less than the boiling point and greater than the boiling point. Let x be the temperature of benzene, For benzene to remain as liquid, its temperature must be between:

42°F < x < 176°F

b) The inequality graph is attached. The graph shows that the temperature of benzene must be between 42°F and 176°F so that it would be a liquid. The Closed circles represent that it is greater than 2.

c) No, This is because at 20° F benzene would not be in liquid form but in solid form. Because the temperature cannot go below 42 before it freezes, she would not have been able to conduct her research .

5 0

3 years ago

13 POINTS- please help me

allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures $(6x+20)^{\circ}$ and $(x+100)^{\circ}$ are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

$6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16$

Then

$(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}$

17. Two parallel lines are cut by transversal. Angles with measures $(2x+12)^{\circ}$ and $(3x-22)^{\circ}$ are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

$2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34$

Then

$(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}$

18. Two parallel lines are cut by transversal. Angles with measures $(6x-7)^{\circ}$ and $(5x+10)^{\circ}$ are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

$6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17$

Then

$(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}$

19. The diagram shows two complementary angles with measures $2x^{\circ}$ and $56^{\circ}$ . The measures of complementary angles add up to $90^{\circ},$ then

$2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17$

Hence,

$2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}$

Check:

$34^{\circ}+56^{\circ}=90^{\circ}$

20. Angles $\angle 1$ and $\angle 2$ are vertical angles. By vertical angles theorem, vertical angles are congruent, so

$m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4$

Hence,

$m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}$

21. $\angle 5$ and $\angle 8$ are supplementary. The measures of supplementary angles add up to $180^{\circ},$ so

$m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34$

Therefore,

$m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}$

7 0

3 years ago

What are the coordinates of the midpoint of the line segment with endpoints J(−6, 3) and K(4, −2) ?

frutty [35]

M = ( (-6+4)/2, (3+-2)/2 )

M = (-1, 1/2)

8 0

3 years ago

Read 2 more answers

out of a group of zebras 6/5 times the square root of the number of zebras are playing on the shore of the tank remaining six ar

MatroZZZ [7]

Answer:

Step-by-step explanation:

(6/5)√x = x - 6

(36/25)x = x² - 12x + 36

0 = x² - 13.44x + 36

x = (13.44 ± √(13.44² - 4(1)(36))) / (2(1))

x = (13.44 ± 6.052569702...) / 2

x = 3.69371... zebras

or

x = 9.74628... zebras

In either case we have some odd fractions of zebras hanging around. This makes me highly suspect that the question is misreported

3 0

3 years ago