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ElenaW [278]
3 years ago
9

In circle M, segment AB is tangent to the circle at point C. AB has endpoints such that AM BM  ,

Mathematics
1 answer:
iren2701 [21]3 years ago
5 0

Answer:

6

Step-by-step explanation:

We can use the geometric mean theorem:

The altitude on the hypotenuse is the geometric mean of the two segments it creates.

In your triangle, the altitude is the radius CM and the segments are AC and BC.

CM = \sqrt{AC \times BC} = \sqrt{ 9 \times 4} = \sqrt{36} = \mathbf{6}\\\text{The radius of the circle M is $\large \boxed{\mathbf{6}}$}

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The width of a rectangle measures (5v-10w)centimeters, and its length measures (2v+3w)centimeters. Which expression represents t
kiruha [24]

Answer:the perimeter of the rectangle =A) (−14w+14v) centimeters

Step-by-step explanation:

Step 1

The perimeter of a Rectangle is given as 2 (l+ w)

If Length = 2v+3w centimeters.

and width =5v-10wcentimeters

Then Perimeter =2 (2v+3w + 5v-10w)

Perimeter=2(7v -7w)

Perimeter= 14v - 14w or can be written as -14w +14v

8 0
3 years ago
2,826 rounded to the nearest tenth
jasenka [17]

Answer:

2,826

Step-by-step explanation:

A tenth is the first place value after the decimal point

In this case, 2,826.<u>0</u>0

To round a number to the tenths place, we look at the hundredths place

If the number is 5 or more, we add 1 to the tenths place, and leave the numbers to the right 0's

If the number is 4 or less, we keep the number as it is in the tenths place, and leave the numbers to the right 0's

In this case, the hundredths place is a 0, which is less than 4, so we keep the 0 in the tenths place, and leave the to the right 0's.

Thus, our final answer is 2,826.

8 0
2 years ago
Prove fermat's theorem for the case where f has a minimum at x0 (show f 0 (x0) = 0)
allochka39001 [22]
Suppose that some value, c, is a point of a local minimum point.

The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.

This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then: \frac{f(c + h) - f(c)}{h} \leq 0 \text{, where h is approaching 0 from the negative side}
As h approaches 0 from the positive side, then: \frac{f(c + h) - f(c)}{h} \geq 0

Thus, f'(c) = 0
6 0
3 years ago
15 points!!
saw5 [17]

Answer:

If the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the triangles are congruent.

Step-by-step explanation:

5 0
3 years ago
I need help with this is 8th grade math
Tresset [83]

Answer:

5 hours

Step-by-step explanation:

Mark recieves 3mg per hour. This can be rewritten as y=3x. Cassie recieves 2x+5. To solve, use substitiution. 3x=2x+5. To solve, subtract "2x" from "3x." You then get x=5.

5 0
2 years ago
Read 2 more answers
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