Question

In circle M, segment AB is tangent to the circle at point C. AB has endpoints such that AM BM  ,

Answer 1

Answer:

6

Step-by-step explanation:

We can use the geometric mean theorem:

The altitude on the hypotenuse is the geometric mean of the two segments it creates.

In your triangle, the altitude is the radius CM and the segments are AC and BC.

$CM = \sqrt{AC \times BC} = \sqrt{ 9 \times 4} = \sqrt{36} = \mathbf{6}\\\text{The radius of the circle M is \large \boxed{\mathbf{6}} }$