3 years ago

I need help with these problems!!!

Mathematics

1 answer:

Tpy6a [65]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

3c+2d=-24 and 2c+5d= -38

Assoli18 [71]

Answer:

c=-4, d=-6

Step-by-step explanation:

3 0

2 years ago

Round 24/43 to the nearest thousandth

WARRIOR [948]

.558 is rounded to the nearest thousandth

3 0

2 years ago

Read 2 more answers

How do you solve the division problem 456÷5?

stiv31 [10]

To find the exact value using trigonometric identities
Exact form 456 divide a by 5
Decimal form 91.2
Mixed number form 91 1
-
5

4 0

2 years ago

What is the value of x in the figure? <br><br><br> x= ?

Otrada [13]

X = 68

Since the angle opposite of it is a right angle, we know that 22 + x has to equal 90 also.

So just take 90 - 22 = 68 degrees

6 0

2 years ago

Read 2 more answers

The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. Assu

m_a_m_a [10]

Answer: 0.0170

Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

i.e. $\mu=23.50$

$\sigma=5$

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let $\overline{x}$ be the sample mean.

Formula : $z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

Then, the probability that the sample mean is at least $25.00 will be :-

$P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z$

Hence, the likelihood the sample mean is at least $25.00= 0.0170

5 0

3 years ago