Given:
t1 = 3.6 h
t2 = 4.5 h
x = speed of boat
y = speed of water
Required:
a) Expression of distance traveled with moving water with 3.6h
Expression of distance traveled with moving water with 4.5h
b) Solve for y
c) Percent of boat's speed is the water current
Solution:
Working formula: distance = velocity*time
a) For travelling downstream, we get the equation
d = (x +y)*3.6
For travelling upstream, we get the equation
d = (x-y)*4.5
b) Setting the distance as equal for travelling upstream or downstream, we arrive at the equation of
(x+y)*3.6 = (x-y)*4.5
3.6x + 3.6y = 4.5x - 4.5y
8.1y =0.9x
y = x/9
c) percentage = 1/9*100% = 11.1%
<em>ANSWERS: a) d = (x+y)*36; d = (x-y)*4.5
</em> <em>b) y = x/9
</em> <em>c) 11.1%</em>
Answer:
.5
Step-by-step explanation:
.5
yellow= .30
orange= .50
green= .10
red- .10
Answer:
9 %
Step-by-step explanation:
The value of x is 3.8
<em><u>Solution:</u></em>
<em><u>Given equation is:</u></em>
We have to solve the equation for "x"
Move the terms so that you end up with only terms involving x on one side of the sign and all the numbers on the other
Therefore, we get
x + 7.4 = 11.2
When we move 7.4 from left side to right side of equation it becomes -7.4
x = 11.2 - 7.4
Subtract 7.4 from 11.2
x = 3.8
Thus value of x is 3.8
