A rocket is launched into the air. The projectile motion of the rocket can be modeled using h(t) = 112t –16t2, where t is the ti me since launch in seconds and h(t) is the height of the rocket at time t. When will the rocket be 196 feet in the air?
2 answers:
H ( t ) = 112 t - 16 t² When the rocket is 196 feet in the air: 196 = 112 t - 16 t² 16 t² - 112 t + 196 = 0 / : 4 4 t² - 28 t + 49 = 0 ( 2 t - 7 )² = 0 2 t - 7 = 0 2 t = 7 t = 7 : 2t = 3.5 s Answer: The rocket will be 196 feet in the air after 3.5 seconds.
Answer:
After 3.5 sec rocket will be at 196 feet in the air.
Step-by-step explanation:
The projectile motion of a rocket can be modeled using h(t) = 112t - 16t²
where t is the time since launch in seconds.
h(t) is the height of the rocket at time t.
we have to calculate when height h is 196 feet.
Now from the given function
196 = 112t - 16t²
-16t² + 112t - 196 = 0
-4t² + 28t - 49 = 0
Or 4t² - 28t + 49 = 0
(2t - 7)² = 0
2t - 7 = 0
t = 7/2 = 3.5 sec
You might be interested in
Answer:
Mean; 5
MEDIAN: 5
Range: 2
Mode: all values appeared just once
Geometric mean: 4.8989794855664
Largest: 6
Smallest: 4
Sum: 10
Count : 2
Answer:
Ready to help soon as we know what that "one" is
answer is $ 12.99
I added 15.75 and 17.50 then took 46.24 -33.25 which equals 12.99
It's 90,000 because standard from uses numbers
Answer:
EVERYONE THAT HAS WATCHED GINNY AND GEORGIA PLEASE GO REVEIW THE SHOW AND GIVE IT 5 STARS. WE NEED A SEASON 2 ..