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marysya [2.9K]
3 years ago
11

What are trigonometric ratios used to find?

Mathematics
2 answers:
defon3 years ago
7 0

Answer:

What are trigonometric ratios used to find?

Well your answer would be: Using Trigonometric ratios to Solve Triangles.


Step-by-step explanation:

The trigonometric ratios can be used to find a lot of information. One of their main purposes is to help you to solve triangles. To solve a triangle means to find the length of all the sides. Also the measure of all the angles.

Hoped this helped, Good Luck and Have a beautiful day!

~Ash W

Dvinal [7]3 years ago
6 0
Well I know it help solve triangles,And to solve a triangle means to find leangth of all sides and the measure of all angles
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Find the GCF<br> 50x^4, -10x^5, 2x^6
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Answer:

2 x^4

Step-by-step explanation:

Recall that the GCF is the greatest of the product of factors that are common to all these three expressions

then for the pure numerical part, the factor common to 50, -10 , and 2 is "2"

and for the variable part x^4 is the largest common to all three expressions.

Therefore the GCF is: 2 x^4

7 0
3 years ago
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A network provider investigates the load of its network. The number of concurrent users is recorded at fifty locations (thousand
beks73 [17]

Answer:

see explaination

Step-by-step explanation:

Using the formulla that

sum of terms number of terms sample mean -

Gives the sample mean as \mu=17.954

Now varaince is given by

s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97

and the standard deviation is s=\sqrt{9.97}=3.16

b) The standard error is given by

\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45

c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1

Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88

d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05

Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96

or a number which is less than 15.83-1.5(4.05)=9.76

As there is no such number so the given sample has no outliers

5 0
3 years ago
Solve for x: −1 &lt; x + 3 &lt; 5
Gnesinka [82]

Answer:

-4<x<2

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask ÷)

7 0
3 years ago
A patient’s systolic blood pressure drops from 210 mmHg to 100 mmHg in 10 minutes after they took nitroglycerin. Calculate the p
denpristay [2]

Answer:

7

Step-by-step explanation:

8 0
3 years ago
A family is relocating from St. Louis, Missouri, to California. Due to an increasing inventory of houses in St. Louis, it is tak
Dafna1 [17]

Answer:

a. Assume that the population has a normal distribution.

b. The 90% confidence interval of the mean sale time for all homes in the neighborhood is between 219.31 days and 240.69 days.

Step-by-step explanation:

Question a:

We have to assume normality.

Question b:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645\frac{35}{\sqrt{29}} = 10.69

The lower end of the interval is the sample mean subtracted by M. So it is 230 - 10.69 = 219.31 days.

The upper end of the interval is the sample mean added to M. So it is 230 + 10.69 = 240.69 days.

The 90% confidence interval of the mean sale time for all homes in the neighborhood is between 219.31 days and 240.69 days.

7 0
3 years ago
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