P( 4) = 13 and Q( 4) = 8, evaluate P( 4) Q(4).
1 answer:
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Answer:
67/5 = 13 2/5
Step-by-step explanation:
Step 1: <u>Define/explain.</u>
An easier way to solve this is by changing the mixed fractions to improper fractions.
To do this, multiply the whole number by the denominator, then add the product to the numerator; the denominator remains the same.
Mixed fraction - a fraction with a whole number.
Improper fraction - a fraction with a numerator larger than the denominator.
Step 2: <u>Solve.</u>
From here, add as usual.
Step 3: <u>Conclude.</u>
You can change the improper fraction to a mixed fraction if you'd like.
To do this, divide the numerator by the denominator.
The amount of times the numerator evenly goes into the denominator is the whole number.
The amount of remaining numbers in the denominator.
The numerator remains the same.
I, therefore, believe the answer to this is 13 2/5.
Answer: 15/91 which is choice B
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There are two methods to find this answer.
Method 1) We have 6 girls and 8+6 = 14 students. The probability of picking a girl is 6/14 = 3/7. After the first girl is chosen, we have 5 girls left out of 14-1 = 13 students overall. The probability of picking another girl (assuming the first selection was a girl) is 5/13. Multiply these probabilities: (3/7)*(5/13) = (3*5)/(7*13) = 15/91
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Method 2) We can use the nCr combination formula. Order does not matter.
We have nCr = 6 C 2 = 15 ways to pick 2 girls. See the attached image below for the steps (figure 1)
Out of nCr = 14 C 2 = 91 ways to pick 2 students. See the attached image below for the steps (figure 2)
So that's another way to get the answer 15/91.
