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Artist 52 [7]
3 years ago
10

P( 4) = 13 and Q( 4) = 8, evaluate P( 4) Q(4).

Mathematics
1 answer:
mariarad [96]3 years ago
7 0
This is a common multiplication problem. Imagine P(4) as x, and Q(4) as y. You are plugging them into the equation x*y. Since x is equal to 13, and y is equal to 8, you are going to plug them into their corresponding variables and multiply. 13 * 8 = 104. The answer is 104.
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Answer:

<u>a(n)=80*(9/10)^(n-1)</u>

Step-by-step explanation:

I think u r confused

this sequence is geometric not arithmetic

HOw we know that ??

when we get a common difference  <u>that must Be equal  </u>

d=72-80=-8  not equal to  d=64.8-72=-7.2

So it is not arithmetic

but when we get the common ratio that also must <u>be equal </u>

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a(n)=a*r^(n-1)

and we have <u>a=80 , r=9/10</u>

Then       <u>a(n)=80*(9/10)^(n-1)</u>

<em>I really hope this helps <3</em>

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How would I solve I need to know Asap and what is the answer
Elanso [62]

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