The last option c is right because each book selected represents the sample from the population of full library books.
We have given that,
Sahira chooses a random sample from the library and records the type of books in the chart below.
Type of Book Number
Fantasy 10
Literature 25
Children’s 4
Nonfiction 11
t, showing the distribution of the number of books in a library.
Also given that Sahira chooses a random sample from the library and records the type of books in the chart below.
Sahira's sample can be said to be representative because given that books are taken at random.
So just because books literature more we cannot say it is not representative II option is not right, because each book was not chosen uniquely, just random books were drawn.
<h3>
What is the population?</h3>
A population is defined as a group of individuals of the same species living and interbreeding within a given area. Members of a population often rely on the same resources, are subject to similar environmental constraints, and depend on the availability of other members to persist over time.
The last option c is right because each book selected represents the sample from the population of full library books.
To learn more about the population visit:
brainly.com/question/27883697
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I believe the first one is h becuase there is a y on the left side.
for the second one just find the slope for the points and see which one doesn't fit in the groups (I would use tables)
and for the last one try writing equations for them.
but idk tho that's just what I would do.
Answer : <em>The</em><em> </em><em>required</em><em> </em><em>ratio</em><em> </em><em>is</em><em> </em><em>(</em><em>1</em><em>4</em><em>m</em><em>-</em><em>6</em><em>)</em><em>:</em><em>(</em><em>8</em><em>m</em><em>+</em><em>2</em><em>3</em><em>)</em><em> </em><em>.</em>
Here we are given that the ratio of sum of first n terms of two AP's is (7n + 1):(4n + 27) .
That is.
As , we know that the sum of n terms of an AP is given by ,
![\small\sf\longrightarrow \pink{ S_n =\dfrac{n}{2}[2a +(n-1)d]} \\](https://tex.z-dn.net/?f=%5Csmall%5Csf%5Clongrightarrow%20%5Cpink%7B%20S_n%20%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%20%2B%28n-1%29d%5D%7D%20%5C%5C)
Assume that ,
- First term of 1st AP = a
- First term of 2nd AP = a'
- Common difference of 1st AP = d
- Common difference of 2nd AP = d'
Using this we have ,
![\small\sf\longrightarrow \dfrac{S_1}{S_2}=\dfrac{\dfrac{n}{2}[2a + (n-1)d]}{\dfrac{n}{2}[2a' +(n-1)d'] } \\](https://tex.z-dn.net/?f=%5Csmall%5Csf%5Clongrightarrow%20%5Cdfrac%7BS_1%7D%7BS_2%7D%3D%5Cdfrac%7B%5Cdfrac%7Bn%7D%7B2%7D%5B2a%20%2B%20%28n-1%29d%5D%7D%7B%5Cdfrac%7Bn%7D%7B2%7D%5B2a%27%20%2B%28n-1%29d%27%5D%20%7D%20%5C%5C)
Now also we know that the nth term of an AP is given by ,
Therefore,
From equation (i) and (iii) ,
Substitute this value in equation (i) ,
Simplify,
![\longrightarrow\sf\small \dfrac{2[a + (m-1)d]}{2[a' + (m-1)d']}=\dfrac{ 14m-6}{8m+23}\\](https://tex.z-dn.net/?f=%5Clongrightarrow%5Csf%5Csmall%20%5Cdfrac%7B2%5Ba%20%2B%20%28m-1%29d%5D%7D%7B2%5Ba%27%20%2B%20%28m-1%29d%27%5D%7D%3D%5Cdfrac%7B%2014m-6%7D%7B8m%2B23%7D%5C%5C)
![\longrightarrow\sf\small \dfrac{[a + (m-1)d]}{[a' + (m-1)d']}=\dfrac{ 14m-6}{8m+23}\\](https://tex.z-dn.net/?f=%5Clongrightarrow%5Csf%5Csmall%20%5Cdfrac%7B%5Ba%20%2B%20%28m-1%29d%5D%7D%7B%5Ba%27%20%2B%20%28m-1%29d%27%5D%7D%3D%5Cdfrac%7B%2014m-6%7D%7B8m%2B23%7D%5C%5C)
From equation (ii) ,
Answer:
the answer is x=y/9 + XZ/9
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
1. A 2. B
Step-by-step explanation:
Whatever happens to x must also happen to y.
For the first question, x is doubled, which means that the value of y is also doubled.
For the second question, if the value of x triples, then the value of y triples as well, which means that it would be multiplied by 3.
We can check to see if these two answers are true by inputting values into the equations.
For the first equation, let's use the example x = 2
y = 5(2)
y = 10
If the value if x doubled, it would become x = 4
y = 5(4)
y = 20
As you can see, when the value of x doubled from 2 to 4, the value of y also doubled from 10 to 20.
You can do something similar for the other equation.
