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ziro4ka [17]
3 years ago
7

Question six about significant figures, please help!

Mathematics
1 answer:
belka [17]3 years ago
8 0

rules to find :- 1 All non zeroes number are significant

2  if zero proceeding the decimal point also work as non zero figure

3 zero are following the decimal point and proceeding the first non zero digit

4 Zero in between 2 non zero digits are also significant

5 if 1 zero follow the decimal point


790  :-    2 significant figures

0.0391 :-  3 significant figures ( follow 3 rule)

81.05  :- 4 significant figures  ( rule 4)

0.000001 :-   1 significant figure

8546 :-        4 significant figures

79.0 :-         3 significant   ( rule 5)

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Step-by-step explanation:

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Given the line of the best fit for a set of data points with equation y=-5x-2.5 what is the residual for the point (3,6)
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Answer:

The residual of the point (3,6) in the equation y=-5(x)-2.5 is = 23.5

Step-by-step explanation:

We have been given point (3,6) where x=3.

Now the equation is y=-5(x)-2.5.

Plugging the value of x=3 in the equation of y=-5(x)-2.5,

we have to find the predicted value of y and y=-5(3)-2.5 =-15-2.5=-17.5.

So y predicted =-17.5.

To find the residual point we have to subtract the actual value from the predicted value.

As actual value of y=6 along with the points (3,6).

Residual point = Actual value - Predicted value.

                        =6 -(-17.5) =23.5

So the residual for the point (3,6) is 23.5.

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3 years ago
Obtain or compute the following quantities.
iVinArrow [24]

Answer:

a) F_{0.05,4,7}=0.16

b) F_{0.05,7,4}=0.24

c) F_{0.95,4,7}=4.12

d) F_{0.95,7,4}=6.09

e) F_{0.99,8,12}=4.50

f) F_{0.01,8,12}=0.18

g) P(F_{5,4} \leq 6.26)=0.95

h) P(0.177 \leq F_{10,5} \leq 4.74)=0.94

Step-by-step explanation:

(a) F0.05, 4, 7 (Round your answer to two decimal places.)

For this case we need a valueof the F distribution with 4 degrees of freedom for the numerator and 7 for the denominator that accumulates 0.05 of the area on the left tail. We can use the following excel code: "=F.INV(0.05,4,7)". And we got:

F_{0.05,4,7}=0.16

(b) F0.05, 7, 4 (Round your answer to two decimal places.)

For this case we need a valueof the F distribution with 7 degrees of freedom for the numerator and 4 for the denominator that accumulates 0.05 of the area on the left tail. We can use the following excel code: "=F.INV(0.05,7,4)". And we got:

F_{0.05,7,4}=0.24

(c) F0.95, 4, 7 (Round your answer to three decimal places.)

For this case we need a valueof the F distribution with 4 degrees of freedom for the numerator and 7 for the denominator that accumulates 0.95 of the area on the left tail. We can use the following excel code: "=F.INV(0.95,4,7)". And we got:

F_{0.95,4,7}=4.12

(d) F0.95, 7, 4 (Round your answer to three decimal places.)

For this case we need a valueof the F distribution with 7 degrees of freedom for the numerator and 4 for the denominator that accumulates 0.95 of the area on the left tail. We can use the following excel code: "=F.INV(0.95,7,4)". And we got:

F_{0.95,7,4}=6.09

(e) the 99th percentile of the F distribution with v1 = 8, v2 = 12 (Round your answer to two decimal places.)

So for this case we need a value on the F distribution with 8 degrees of freedom for the numerator and 12 for the denominator that accumulates 0.99 of the area on the left tail. And we can use the following excel code: "=F.INV(0.99,8,12)". And we got:

F_{0.99,8,12}=4.50

(f) the 1st percentile of the F distribution with v1 = 8, v2 = 12 (Round your answer to three decimal places.)

So for this case we need a value on the F distribution with 8 degrees of freedom for the numerator and 12 for the denominator that accumulates 0.01 of the area on the left tail. And we can use the following excel code: "=F.INV(0.01,8,12)". And we got:

F_{0.01,8,12}=0.18

(g) P(F ≤ 6.26) for v1 = 5, v2 = 4 (Round your answer to two decimal places.)

For this case we want to find the probability that the F distribution with 5 degrees on the numerator and 4 on the denominator would be less or equal than 6.26. We can use the following excel code: "=F.DIST(6.26,5,4,TRUE)". And we got

P(F_{5,4} \leq 6.26)=0.95

(h) P(0.177 ≤ F ≤ 4.74) for v1 = 10, v2 = 5 (Round your answer to two decimal places.)

For this case we want to find the probability that the F distribution with 10 degrees on the numerator and 5 on the denominator would be between 0.177 and 4.74. We can use the following excel code: "=F.DIST(4.74,10,5,TRUE)-F.DIST(0.177,10,5,TRUE)". And we got

P(0.177 \leq F_{10,5} \leq 4.74)=0.94

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The zeros of a function are the x-values which make y=0. When we look at them on a graph, it's the places where the graph intersects the x-axis.
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