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kap26 [50]
3 years ago
12

Find the values of the variables in the parallelogram. The diagram is not drawn to scale. Use theorems involving parallel lines

and the the sum of the angles of a triangle.

Mathematics
1 answer:
Ksju [112]3 years ago
8 0

Answer:

Y=52(alternate interior angles)

X+y+z= x+52+72=180

= x+ 124=180

= x = 180-124=56

X=56

Z= 72 ( opposite angles of parallelogram)

Thus it is the last option

X=56 , y=52 , z = 72

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One year, in school A, 162 students leave and 109 go to university. In school B, 75 students leave and 68 go to university. Comp
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in school a , 67.3 % of leaving students go to university.

in school b ,90.7% of leaving students go to university

Step-by-step explanation:

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4 years ago
PLEASE HELPPPPPP<br> The perimeter is 50 ft and the length is 15 ft.<br> What's the width?
SVEN [57.7K]

Answer:

10

Step-by-step explanation:

I assume it's a rectangle, therefore:

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3 years ago
seven times a number is twelve more than three times the number. write an equation, this is urgent! pls hurry up!
egoroff_w [7]

Answer:

n=3

Step-by-step explanation:

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7 0
2 years ago
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26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
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