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2 years ago

Brad drives 527 miles on 17 gallons. How many miles does Brad drive on one gallon?

Mathematics

2 answers:

Step2247 [10]2 years ago

5 0

31 miles an hour just divide 527 by 17

Nostrana [21]2 years ago

5 0

Answer:

31 miles per hour

Step-by-step explanation:

527/17 = 31 miles per hour when you divide the two your taking your miles that the car drove and the gallons it needed and getting your answer from that

hope this helps and make me brainliest please

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jeka94

Answer:

The answer would be C)5

Step-by-step explanation:

The unknown triangle is half of the size of the original triangle, The right side measurement basically hints to the actual answer.

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2 years ago

3(c+5)=12. Distributive property

avanturin [10]

Answer:

c = -1

Step-by-step explanation:

3(c+5)=12

3 × c = 3c

3 × 5 = 15

3c + 15 = 12

3c = -3

c = -3 ÷ 3 = -1

Check:

3(-1+5)=12

-3 + 15 = 12

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2 years ago

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The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

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2 years ago

Marsha recorded the time it took seven children of different ages to run one lap around the track.

max2010maxim [7]

The answer is C. 205.

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2 years ago

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Suppose that in 20% of all traffic accidents involving an injury, driver distraction in some form (for example, changing a radio

Ghella [55]

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3 years ago