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3 years ago

Does anyone understand this?

Mathematics

2 answers:

Aleonysh [2.5K]3 years ago

3 0

VX is a bisector which is half the length of TU

VX = 50/2 = 25

nika2105 [10]3 years ago

3 0

Answer:

Step-by-step explanation:

TU= 50

50/2=25

VX=25

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Simplify the following

Goshia [24]

Answer:

Step-by-step explanation:

Using the rules of logarithms

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Then

$log_{x}$ $x^{9}$

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3 years ago

If a = 9 and b = 4, what is the value of 2a<br> -b?

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

2(9)-4=14

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3 years ago

Please help me pls ASAP thank YOUU

Mama L [17]

Answer:

I think D

Step-by-step explanation:

Sorry if it's wrong, but it's the only one I think makes sense. Brainlist me if u get it right! :)

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3 years ago

HELP!!!!!!! ME!!!!!!! ASAP!!!

BartSMP [9]

Hey there!

The answer is most likely option A

Because,

First, we have to add by $5$ on each of your sides!

Like: $\frac{1}{3}x - 5 + 5 \\ \\ y + 5$

We get this as our answer for this portion: $\frac{1}{3}x = y + 5$

Nextly, we have to divide by $\frac{1}{3}$ on each of your sides

Like: $\frac{1/3x}{1/3} = \frac{y +5 }{1/3}$

Therefore your answer would be: $x = 3y + 15$

Good luck on your assignment and enjoy your day!

~ $LoveYourselfFirst:)$

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3 years ago

A random sample of individuals is selected from a population with μ , and a treatment is administered to each individual in the

Ghella [55]

Answer:

A) THE MEAN DIFFERENCE = 22.2 - 20 = 2.2

B) HERE WE NEED TO CALCULATE THE MARGIN OF ERROR

AS GIVEN THE VARIANCE = 384

THEREFORE STANDARD DEVIATION = (384)^(1/2) = 19.59

THE MARGIN OF ERROR = STANDARD DEVIATION / SQRT(N) = 19.59/SQRT(25) = 19.59/5 = 3.91

C) AS THE SAMPLE SIZE IS LESS THEN 30 THEREFORE WE WILL DO IT BY THE T TEST

We need to test the null H0 : µ = 20 against the TWO-sided alternative H1 : µ\neq 20, at level α = 0.05. Since n is SMALL, we will do a SMALL-sample T-test. The rejection region is T >Tα = 1.96OR T<-Tα = -1.96, using the normal table.

T= (X − µ0) /(S/√ n) = (22.2 − 20)/( 19.59/ √ 25) = 0.56 Since T = 0.56 < 1.96, H0 is ACCEPTED. Thus, there is significant evidence at 5% signifi- cance level .

Step-by-step explanation:

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4 years ago