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Ber [7]
3 years ago
15

3500 in standard form

Mathematics
1 answer:
azamat3 years ago
4 0

Answer:

3.5 × 10³

Step-by-step explanation:

Leave one whole number (1 to 9) before the decimal point.

3.500

Count how many decimal places it moved to get next to 3.

There are about 3 decimal places moved.

So,

3.5 × 10³ is the answer

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Prove these identities <br>(i) secx cosecx - cotx = tanx<br>​
brilliants [131]

Answer:

(A)\frac 1 {cosx} \frac 1 {sin x}  - \frac {cosx} {sin x} = \frac {sin x} {cosx} \\\\(B)\frac{1-cos^2 x }{cos x sin x} = \frac {sin x} {cosx} \\\\(C) \frac{(sin^2x + cos^2x)-cos^2 x }{cos x sin x} = \frac {sin x} {cosx} \\\\(D) \frac{sin^2x }{cos x sin x} = \frac {sin x} {cosx}\\\\(E)\frac {sin x}{cos x} = \frac {sin x}{cos x}

In step A, you replace all trigonometric functions with their definitions in terms of sine and cosine.

In step B, you add the two together as you add fractions.

In step C, you replace 1 with the sum of the squares of sine and cosine.
In step D, you add the cosine terms together so they disappear.

In step E, finally, you divide numerator and denominator by sin x.

3 0
2 years ago
(x-3y+ 3z=-4<br><br> 2x+3y-z =15<br><br> (4x-3y- z=19<br><br> - What is the solution to the system?
lesya [120]

Answer:

x=5,y=1 and z=-2

Step-by-step explanation:

We are given that system of equation

x-3y+3z=-4 (I equation)

2x+3y-z=15  (II equation )

4x-3y-z=19  (III equation )

Equation II multiply by 3 then add  with equation I

Then, we get

7x+6y=41 ....(Equation IV)

Subtract equation II from equation III then we get

2x-6y=4  (equation V)

Adding equation IV and equation V then, we get

9x=45

x=5

Substitute x=5 in equation V then, we get

2(5)-6y=4

10-6y=4

6y=10-4=6

y=1

Substitute x=5 and y=1 in equation then, we get

5-3(1)+3z=-4

2+3z=-4

3z=-4-2=-6

z=\frac{-6}{3}=-2

Hence, the solution for the given system of equation is given by

x=5,y=1 and z=-2

7 0
3 years ago
The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When
atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

A=w\ell

Where <em>w</em> is the width and <em>l</em> is the length.

We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>

\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]

By the Product Rule:

\displaystyle \frac{dA}{dt}=\frac{dw}{dt}\ell +\frac{d\ell}{dt}w

Since we know that dl/dt = 6 and that dw/dt = 5:

\displaystyle \frac{dA}{dt}=5\ell + 6w

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

\displaystyle \frac{dA}{dt}=5(12)+6(4)=84\text{ cm}^2\text{/s}

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

8 0
3 years ago
there were 629,000 women motorcyclists, up from 447,000 eight years ago. what's the percentage of increase?
Mila [183]
This is the formula for percentage increase and decrease

6 0
3 years ago
Complete the puzzle by clicking on the puzzle piece that contains equivalent expression.
Liono4ka [1.6K]

Answer:

 -5 when ...

Step-by-step explanation:

The rules of exponents can help you simplify the given product.

<h3>Rules</h3>

  (a/b)^c = (a^c)/(b^c)

  (ab)^c = (a^c)(b^c)

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

<h3>Application</h3>

  \left(\dfrac{x}{y}\right)^2(-x^2y)^3=\\\\\dfrac{x^2(-1)^3(x^2)^3y^3}{y^2}=-x^{2+2\cdot3}y^{3-2}=-x^8y

This expression does not match any of those offered.

When x=-1 and y=5, this becomes ...

  -(-1)^8(5)=\boxed{-5}

8 0
1 year ago
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