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3 years ago

3500 in standard form

Mathematics

1 answer:

azamat3 years ago

4 0

Answer:

3.5 × 10³

Step-by-step explanation:

Leave one whole number (1 to 9) before the decimal point.

3.500

Count how many decimal places it moved to get next to 3.

There are about 3 decimal places moved.

So,

3.5 × 10³ is the answer

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Prove these identities (i) secx cosecx - cotx = tanx

brilliants [131]

Answer:

$(A)\frac 1 {cosx} \frac 1 {sin x} - \frac {cosx} {sin x} = \frac {sin x} {cosx} \\\\(B)\frac{1-cos^2 x }{cos x sin x} = \frac {sin x} {cosx} \\\\(C) \frac{(sin^2x + cos^2x)-cos^2 x }{cos x sin x} = \frac {sin x} {cosx} \\\\(D) \frac{sin^2x }{cos x sin x} = \frac {sin x} {cosx}\\\\(E)\frac {sin x}{cos x} = \frac {sin x}{cos x}$

In step A, you replace all trigonometric functions with their definitions in terms of sine and cosine.

In step B, you add the two together as you add fractions.

In step C, you replace 1 with the sum of the squares of sine and cosine.
In step D, you add the cosine terms together so they disappear.

In step E, finally, you divide numerator and denominator by $sin x$ .

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2 years ago

(x-3y+ 3z=-4 2x+3y-z =15 (4x-3y- z=19 - What is the solution to the system?

lesya [120]

Answer:

x=5,y=1 and z=-2

Step-by-step explanation:

We are given that system of equation

$x-3y+3z=-4$ (I equation)

$2x+3y-z=15$ (II equation )

$4x-3y-z=19$ (III equation )

Equation II multiply by 3 then add with equation I

Then, we get

$7x+6y=41$ ....(Equation IV)

Subtract equation II from equation III then we get

$2x-6y=4$ (equation V)

Adding equation IV and equation V then, we get

$9x=45$

$x=5$

Substitute x=5 in equation V then, we get

$2(5)-6y=4$

$10-6y=4$

$6y=10-4=6$

$y=1$

Substitute x=5 and y=1 in equation then, we get

$5-3(1)+3z=-4$

$2+3z=-4$

$3z=-4-2=-6$

$z=\frac{-6}{3}=-2$

Hence, the solution for the given system of equation is given by

x=5,y=1 and z=-2

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3 years ago

The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When

atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

$A=w\ell$

Where w is the width and l is the length.

We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to t, where w and l are both functions of t:

$\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]$