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3 years ago

13

A fisherman can buy either 6 larvae and 4 worms for 13 dollars or 7 larvae and 4 worms for 12 dollars. How much is the price of

worms and larvae?

1 answer:

Gemiola [76]3 years ago

3 0

Answer:

It seems illogical,cannot be calculated

Step-by-step explanation:

Why the fisherman can buy one more larvae but using less money?

You might be interested in

3(5x + 7) = 30 + 15x how many solutions

Xelga [282]

Answer:

No solution

Step-by-step explanation:

3(5x+7) = 30 + 15x

DISTRIBUTE

15x+21 = 30+15x

15x-15x = 0

So no solution

8 0

2 years ago

Read 2 more answers

Cameron is older than Hassan. Their ages are consecutive integers. Find Cameron's

Alexxandr [17]

Answer:

25

Step-by-step explanation:

So consecutive integers, just means they're separated by a value of 1. This can be generally expressed as "a, a+1" where these two values would be consecutive integers assuming "a" is an integer.

So let's express Hassan's age as the variable "x", since it's unknown. Since Cameron is older, and by definition of a consecutive integer, Cameron's can be expressed as "x+1"

So the equation we need to set up is Cameron's age + 5(Hassan's age) = 145

So we can substitute the variables we defined to express Cameron and Hassan's age: $(x+1) + 5(x) = 145$

Distribute the 5: $x+1+5x$

Add like terms: $6x+1 = 145$

Subtract 1 from both sides: $6x=144$

Divide both sides by 6: $x=24$

Since we used "x" to represent Hassan's age, Hassan's age is 24. Since we used "x+1" to represent Cameron's age, Cameron's age is "24+1" which is just 25

6 0

2 years ago

If the demand function for a commodity is given by the equation

Jet001 [13]

Answer:

q=26.92 p=31.13

Step-by-step explanation:

$p^{2} +16q=1400\\\\q=\frac{1400-p^{2} }{16} ;\\\\700-p^{2} +10q=0\\\\q=\frac{p^{2}-700 }{10} ;\\\\$

$q=q\\\\\frac{1400-p^{2} }{16} =\frac{p^{2}-700 }{10} \\\\10(1400-p^{2})=16(p^{2}-700)\\\\14000-10p^{2}=16p^{2}-11200\\\\14000+11200=16p^{2}+10p^{2}\\\\25200=26p^{2}\\\\p^{2}=\frac{25200}{26} \\\\p=+\sqrt{\frac{25200}{26}} \\\\p=31.13$

replace p in any equation and

$q=\frac{1400-p^{2} }{16} \\\\q=\frac{1400-(31.13)^{2} }{16}\\\\q=26.92$

3 0

3 years ago

I need helpppp (10 points )

irga5000 [103]

Answer: The flagpole is about 22.3 feet tall.

This is roughly the size of a two story building, assuming each floor is 10 feet or so.

Since this height is under 25 ft, this flagpole is in compliance with the regulation.

=====================================================

Work Shown:

The horizontal leg of the triangle is 36 ft. This is the adjacent leg to the reference angle 25 degrees.

The vertical leg of the triangle is x-5.5, and this leg is the opposite side to the reference angle 25 degrees.

Use the tangent rule to connect the opposite and adjacent sides.

Solve for x.

tan(angle) = opposite/adjacent

tan(25) = (x-5.5)/36

36*tan(25) = x-5.5

x-5.5 = 36*tan(25)

x = 36*tan(25)+5.5

x = 22.28707569358

x = 22.3 ft is the approximate height of the flagpole

Make sure your calculator is in degree mode.

The height is not over 25 ft, so this flagpole meets the requirements.

4 0

3 years ago

Please someone help me!! Look at picture. Also write as it expression.

Fynjy0 [20]

Answer:hi there!that same guy did that w my question too :( i’m reporting his answers. i will help u out tho ahah. the answer is 470(32-n). i hope this helps :). have a good dayyy

Step-by-step explanation:

6 0

3 years ago