<img src="https://tex.z-dn.net/?f=3x%20-%20%285x%20-%209%29%20%3D%207%20-%204%28x%20%2B%201%29" id="TexFormula1" title="3x

All categories

icang [17]

3 years ago

- 9) = 7 - 4(x + 1)" alt="3x - (5x - 9) = 7 - 4(x + 1)" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Montano1993 [528]3 years ago

8 0

$3x-(5x-9)=7-4(x+1)\\\\3x-5x+9=7-4x-4\\\\-2x+9=-4x+3\ \ \ \ |-9\\\\-2x=-4x-6\ \ \ \ |+4x\\\\2x=-6\ \ \ \ |:2\\\\x=-3$

You might be interested in

At 86 km/h, how many miles can you travel in 30 minutes? Round to the nearest hundredth. Use 1 mi = 1.6 km.

Ray Of Light [21]

Answer:

26.875 = 26.88

86km = 60 minutes

86km/2=

43/1.6(kilometers in miles)

26.88

hope this helps uwu

4 0

3 years ago

Minimum Average Cost

Dahasolnce [82]

Answer:

a) $\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}$

b) $\bar{C}(x)=5.81$

Step-by-step explanation:

Given that

C = 100 + 25 x - 120 ln x ,x ≥ 1.

The average cost function given as

$\bar{C}(x)=\dfrac{C(x)}{x}$

$\bar{C}(x)=\dfrac{100 + 25 x - 120 \ln x}{x}$

$\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx{x}$

Therefore

$\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}$

To find average minimum cost

$\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}$

$\dfrac{d\bar{C}(x)}{dx} = -\dfrac{100}{x^2} +0-120\times \dfrac{1-lnx}{x^2}$

$0 = -\dfrac{100}{x^2} +0- 120\times \dfrac{1-lnx}{x^2}$

100 + 120 (1-lnx) = 0

$lnx=\dfrac{220}{120}$

ln x =1.833

$x=e^{1.833}$

x=6.25

$\bar{C}(x)=\dfrac{100}{6.25}+25-120\dfrac{ln6.25}{6.25}$

$\bar{C}(x)=5.81$

6 0

3 years ago

Prove the following statement by contradiction using an indirect proof. In a triangle angle A = 90°, then the triangle is a righ

kati45 [8]

Answer:

I prefer taking B

Step-by-step explanation : because when the degree is 90 than it should be a right triangle

3 0

4 years ago

Solve 7m+2n=21 and 10m+4n=-10 with substitution

schepotkina [342]

I hope this helps you

10m+4n= -10

5m+2n= -5

-5m-2n= 5

7m+2n-5m-2n= 21+5

5m=26 m= 26/5

5.26/5+2n= -5

26+2n= -5

2n= -31

n= -31/2

3 0

3 years ago

In the diagram below rs is the perpendicular Bisector of PQ

Makovka662 [10]

No idea what is this for

3 0

3 years ago

Read 2 more answers