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lianna [129]
3 years ago
5

−4.8f+6.4=−8.48 What does f stand for?

Mathematics
1 answer:
Nataly [62]3 years ago
3 0

Answer:F is a unknown number

Step-by-step explanation:Isolate the variable

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Help!! I need an answer asap!! <br><br> Given a∥b, find m∠1 = 71º. <br> Find: m∠5, m∠8
Sindrei [870]

Answer:

m<5 = 71 and m<8 = 109

Step-by-step explanation:

m<1 is equivalent to m<5 and m<2 is equivalent to m<8.

5 0
3 years ago
Read 2 more answers
If the given figure is rotated 180° around the origin, what are the new coordinates of point Z? Z= (6,-9)
Nitella [24]

Answer:

Step-by-step explanation:

Rule for 180 rotation: (x,y) becomes (-x,-y)

So (6,-9) becomes (-6,9)

5 0
3 years ago
Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. A two-c
natali 33 [55]

Answer:  By the slope formula.

Step-by-step explanation:

Given: ABC is a triangle (shown below),

In which A≡(6,8), B≡(2,2) and C≡(8,4)

And, D and E are the mid points of the line segments AB and BC respectively.

Prove: DE║AC and DE = AC/2

Proof:

Since, And, D and E are the mid points of the line segments AB and BC respectively.

Therefore, By mid point theorem,

coordinate of D are (\frac{2+6}{2} , \frac{2+8}{2} ) = (\frac{8}{2} , \frac{10}{2} )= (4,5)

Coordinate of E are  (\frac{2+8}{2} , \frac{2+4}{2} ) = (\frac{10}{2} , \frac{6}{2} )= (5,3)

By the distance formula,

DE=\sqrt{(5-4)^2+(3-5)^2}=\sqrt{5}

AC=\sqrt{(8-6)^2+(4-8)^2}=2\sqrt{5}

By the slope formula,

Slope of AC = \frac{4-8}{8-6} = \frac{-4}{2} = -2

Slope of DE =  \frac{3-5}{5-4} = \frac{-2}{1} = -2


            Statement                                              Reason

1. The coordinate of D are (4,5)  and           1. By the midpoint formula

the coordinate of  E are (5,3)

2. The length of DE = √5                            2. By the Distance formula

The length AC = 2√5 ⇒ Segment DE

is half the length of segment AC

3. The slope of DE = -2 and the                3. By the slope formula

slope of AC = -2

4. DE║AC                                                   4. Slopes of parallel lines are equal


7 0
3 years ago
Read 2 more answers
3(2v-1)=6v-4 can someone pls help me with this
ZanzabumX [31]

Answer:

Step-by-step explanation:

dy/dx= -(2x+3y+1)/(3x-2y+1)

Let x= X+p. and y = Y+q. then dy/dx = dy/dX.

dy/dX= -(2X+2p+3Y+3q+1)/(3X+3p-2Y-2q+1) =

dy/dX = -{2X+3Y+(2p+3q+1)}/{3X-2Y+(3p-2q+1)}

Now 2p+3q+1=0……………..(1)

3p-2q +1=0…………………………(2)

p/(3+2)=q/(3–2)=1/(-4–9)

8 0
3 years ago
HELP ASAP
Alex787 [66]

<span>v(x)=(s/t)
= (3x - 6) / (-3x+6)
= [3(x-2)] / [-3(x-2)] --> 3 is factored out
= 1/-1 </span>---> common terms are cancelled out. 
= -1 ---> This is the simplified formula.

To find the domain, we equate the denominator to 0.
-3x+6 = 0
3x = 6
x = 2
Domain: all values except 2.

w(x)=(t/s)(x)
= (-3x+6)x / (3x-6)
= [-3x(x-2)] / [3(x-2)] --> 3 is factored out
= -x --> The common terms are cancelled out. This is the simplified formula.

Solving for domain:
3x-6 = 0
3x = 6
x = 2
Domain: all values except 2.

4 0
3 years ago
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