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zvonat [6]
3 years ago
13

If the null hypothesis of an experiment is “The true mean weight of the geese is greater than 40 pounds” what is the alternate h

ypothesis?
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
5 0

Answer:

<em>"The true mean weight of the geese is less than or equal to 40 pounds"</em>

<em></em>

Step-by-step explanation:

<u>Something (or some value) can be either equal to, greater than, or less than another thing (another value).</u>

Null Hypothesis is what is given and Alternate is what we are testing.

Since Null Hypothesis is given that the mean weight is GREATER THAN 40 pounds, the ALTERNATE HYPOTHESIS would be the mean weight is either EQUAL TO or LESS THAN 40 pounds.

Thus, alternate hypothesis is <em>"The true mean weight of the geese is less than or equal to 40 pounds"</em>

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Matt gets paid at home for doing extra chores. Last week, he did 6 loads of laundry and 1
emmasim [6.3K]

Matt earns $4 and $3 for 1 load of laundry and 1 load of dishes respectively

<u>Solution:</u>

Given, Matt gets paid at home for doing extra chores.

We have to find How much does Matt earn for completing each type of chore?

Let the amount for 1 load of laundry be m and amount for 1 load of dish be n.

Now, last week, he did 6 loads of laundry and 1 load of dishes, and his parents paid him $27.

Then, 6 \times amount for 1 load of laundry + 1 \times amount for 1 load of dish = 27

\rightarrow 6 \mathrm{m}+\mathrm{n}=27 \rightarrow(1)

The week before, he finished 1 load of laundry and 9 loads of dishes, earning a total of $31

Then, 1 \times amount for 1 load of laundry + 9 \times amount for 1 load of laundry = 31  ⇒m + 9n = 31 ⇒ (2)

Now let us solve equations (1) and (2)

0 – 53n = - 159

-53n  = -159  

53n = 159

n = 3

Now, substitute n value in (1) ⇒ 6m + 3 = 27 ⇒ 6m = 24 ⇒ m = 4

Hence, matt earns $4 and $3 for 1 load of laundry and 1 load of dishes respectively.

8 0
3 years ago
System of Equations Problem
aksik [14]

Sarah bought 3 first class tickets and 7 coach tickets.

Step-by-step explanation:

Given,

Number of people = 10

Total amount spent on tickets = $4830

Cost of each coach ticket = $270

Cost of each first class ticket = $980

Let,

x be the number of coach tickets

y be the number of first class tickets

According to given statement;

x+y=10      Eqn 1

270x+980y=4830   Eqn 2

Multiplying Eqn 1 by 270

270(x+y=10)\\270x+270y=2700\ \ \ Eqn\ 3\\

Subtracting Eqn 3 from Eqn 2

(270x+980y)-(270x+270y)=4830-2700\\270x+980y-270x-270y=2130\\710y=2130

Dividing both sides by 710

\frac{710y}{710}=\frac{2130}{710}\\y=3

Putting y=3 in Eqn 1

x+3=10\\x=10-3\\x=7

Sarah bought 3 first class tickets and 7 coach tickets.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/96882
  • brainly.com/question/96535

#LearnwithBrainly

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3 years ago
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