If y varies directly as x, and y =15 as x=3, find y for the x-value of 4.

Someone please help me with this problem!!! I really need help and I don’t understand it!! If you know it please explain how you

nikitadnepr [17]

Distance = Rate * Time where the asterisk represents multiplication

We can isolate the rate if we divide both sides by the time. So we'll end up with this formula
Rate = Distance/Time
which can be written as
r = d/t

The distance is measured in feet while the time is measured in minutes. The rate r is measured in feet per minute. If the speed was 10 feet per minute, then this would mean that the object travels 10 feet every minute. Or put another way, when one minute passes by, the object has traveled 10 feet.

How did I get "feet per minute" from the equation r = d/t?
Well the units for "d" are in feet, and the units for "t" are in minutes

So writing "d/t" would turn into "feet/minute" when we think of the units only (ignore the actual numbers). Then we rewrite "feet/minute" into "feet per minute" as they mean the same thing, just written different ways.

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Answer: The units for the speed or rate are in feet per minute

3 0

3 years ago

An aquarium tank is 3 feet long 1 foot wide and 2 feet high how many gallons of water would it take to fill the tank two thirds

m_a_m_a [10]

Answer: i believe it'll take 6 gallons to fill up the tank two thirds full

Step-by-step explanation: 3 x 1 x 2 = 6 gallons

6 0

2 years ago

Can someone tell me… Given the right triangle ABC, what is the value of tan(A)?

sergey [27]

Answer:

C

Step-by-step explanation:

tanA = $\frac{opposite}{adjacent}$ = $\frac{BC}{AC}$ = $\frac{24}{10}$ = $\frac{12}{5}$ → C

6 0

3 years ago

The table gives estimates of the world population, in millions, from 1750 to 2000. year population year population 1750 790 1900

Tems11 [23]

The poopulation exponential model is given by

$P(t)=P_0e^{kt}$

Where, P(t) is the population after year t; Po is the initial population, t is the number of years from the starting year; k is the groth constant.

Given that the population in 1750 is 790 and the population in 1800 is 970, we obtain the population exponential equation as follows:

$970=790e^{50k} \\ \\ \Rightarrow e^{50k}=1.228 \\ \\ \Rightarrow 50k=\ln{1.228}=0.2053 \\ \\ \Rightarrow k=0.0041$

Thus, the exponential equation using the 1750 and the 1800 population values is $P(t)=790e^{0.0041t}$

The population of 1900 using the 1750 and the 1800 population values is given by

$P(t)=790e^{0.041\times150} \\ \\ =790e^{0.6158}=790(1.8511) \\ \\ =1,462$

The population of 1950 using the 1750 and the 1800 population values is given by

$P(t)=790e^{0.041\times200} \\ \\ =790e^{0.821}=790(2.2729) \\ \\ =1,796$

From the table, it can be seen that the actual figure is greater than the exponential model values.

7 0

3 years ago

A train leaves the train station and travels at a speed of 45 miles per hour on the way to drop off cargo at a warehouse. When t

ruslelena [56]

Lo siento :( perdonameeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee soy Principiante

6 0

3 years ago

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