Question

Let B = −1 1 −3

Answer 1

Answer:

Remember that in the transpose matrix of the matrix A, the entry $a_{ij}$ of A will be the entry $a_{ji}$ of $A^T$.

Then if

$B=\left[\begin{array}{ccc}-1&1&-3\\0&2&3\end{array}\right]$, $B^T=\left[\begin{array}{ccc}-1&0\\1&2\\-3&3\end{array}\right]$

Then

$B^TB=\left[\begin{array}{ccc}1&-1&3\\-1&5&3\\3&3&18\end{array}\right]$