Answer:
It would be $31.80
Step-by-step explanation:
First thing you want to do is to take 6% of $30, which is $1.80.
Add that $1.80 to $30 to get the price after sales tax.
X^2 - 6x = 20
x^2 - 6x + 9 = 20 + 9
(x - 3)^2 = 29
x - 3 = (+-) sqrt 29
x = 3 (+-) sqrt 29
x = 3 (+-) 5.39
x = 3 + 5.39 = 8.39 <=
x = 3 - 5.39 = - 2.39 <=
(-14/9)x3/5x(-4/7)x15/16
=2/3x3/4
=1/2
Answer:
- (x-4.5)^2 +(y +5)^2 = 30.25
- x = (1/8)y^2 +(1/2)y +(1/2)
- y^2/36 -x^2/64 = 1
- x^2/16 +y^2/25 = 1
Step-by-step explanation:
1. Complete the square for both x and y by adding a constant equal to the square of half the linear term coefficient. Subtract 15, and rearrange to standard form.
(x^2 -9x +4.5^2) +(y^2 +10y +5^2) = 4.5^2 +5^2 -15
(x -4.5)^2 +(y +5)^2 = 30.25 . . . . . write in standard form
Important features: center = (4.5, -5); radius = 5.5.
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2. To put this in the form x=f(y), we need to add 8x, then divide by 8.
x = (1/8)y^2 +(1/2)y +(1/2)
Important features: vertex = (0, -2); focus = (2, -2); horizontal compression factor = 1/8.
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3. We want y^2/a^2 -x^2/b^2 = 1 with a=36 and b=(36/(3/4)^2) = 64:
y^2/36 -x^2/64 = 1
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4. In the form below, "a" is the semi-axis in the x-direction. Here, that is 8/2 = 4. "b" is the semi-axis in the y-direction, which is 5 in this case. We want x^2/a^2 +y^2/b^2 = 1 with a=4 and b=5.
x^2/16 +b^2/25 = 1
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The first attachment shows the circle and parabola; the second shows the hyperbola and ellipse.
Answer:
Assume:
(angle) RSB and angle (LSA) = D
and (line) ASR and (line) LSB is striaght then
(9x +27) + D = 180
(6x + 66) + D = 180
9x + D = 153
6x + D = 114
substitute
6x + D = 114
D = 114 - 6 x
9x + (114 - 6x) =153
3x = 39
x = 13
D = 114 - 6(13)
D=36
Step-by-step explanation: