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oksano4ka [1.4K]
3 years ago
13

How do you use the limit definition of the derivative to find the derivative of f(x)=1/x?

Mathematics
1 answer:
guapka [62]3 years ago
6 0
Example 1. Let us start with the functionf(x) = x2. We have 




So 




which means f '(a) = 2a.

What about the derivative of f(x) = xn. Similar calculations, using the binomial expansion for (x+y)n (Pascal's Triangle), yield 




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At which values of x does the function F(x) have a vertical asymptote? Check all that apply. F(x)=2/3x(x-1)(x 5).
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The function F(x) have a vertical asymptote at x =0 and x =1.

Given that

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

We have to determine

At which value the function F(x) has a vertical asymptote.

According to the question

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:

Then,

\rm 3x (x-1) (x^5)= 0

\rm x^5 =0, \ \  x=0\\\\ x-1 = 0, \ \ x =1\\

The value of x is 0 and 1.

Hence, the function F(x) have a vertical asymptote at x =0 and x =1.

To know more about Parabola click the link given below.

brainly.com/question/12868913

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