Question

Y-3x=3 and x-2y=4 using elimination method​

Answer 1

Answer:

x = -2

y = -3

Step-by-step explanation:

$y-3x=3--------(1) \\ x-2y=4 --------(2)\\ -3x +y =3 ----------(1)\\x-2y =4-----------(2)\\Multiply -equation(1)-by-the-coefficient-of x -in-equation(2)\\Multiply -equation(2)-by-the-coefficient-of x -in-equation(1)\\ -3x +y =3 ----------(1)\times 1\\x-2y =4-----------(2)\times -3\\\\-3x+y = 3 -----(3)\\-3x +6y = -12----(4)\\Subtract -equation(4)-from-equation(3)\\-5y =15\\\frac{-5y}{-5} =\frac{15}{-5} \\y = -3$

$Substitute ; -3 -for;y -in -equation (1) or (2)\\-3x +y =3 ----------(1)\\-3x + (-3)=3\\-3x-3 =3\\-3x= 3+3\\-3x=9\\\frac{-3x}{-3} = \frac{9}{3} \\x = -2$

Answer 2

Answer:

x = -2, y = -3

Step-by-step explanation:

y - 3x = 3

x - 2y = 4

-3x + y = 3

x - 2y = 4

-6x + 2y = 6

x - 2y = 4

Add the equations.

-5x = 10

x = -2

Substitute -2 for x in the first original equation and solve for y.

y - 3x = 3

y - 3(-2) = 3

y + 6 = 3

y = -3

Answer: x = -2, y = -3