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Arisa [49]
3 years ago
13

In this problem, the tapes used were assumed to be 30.0 m long. Later, when the tapes were standardized, they were found to have

different tape lengths. Determine the correct distance measured if the measured distance was 1858.23 m, and the correct tape length was 29.97 m. Use two decimal places
Mathematics
1 answer:
romanna [79]3 years ago
3 0

Answer:

1856.37 m

Step-by-step explanation:

When the tapes were taken as 30.0 m long, the measured distance was 1858.23 m. This is equivalent to \dfrac{1858.23}{30}=61.941 tapes.

With the correct tape length now 29.97 m, the measured distance is

29.97\times61.941 \text{ m} = 1856.37177  \text{ m} = 1856.37  \text{ m} to 2 decimal places.

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3 years ago
Which term of ap 30,27,24is0
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Answer:

11th term is 0

Step-by-step explanation:

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8 0
2 years ago
What is the slope of a line that is perpendicular to the line whose equation is 7x−3y=107x−3y=10?
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kherson [118]
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3 years ago
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