Clip art, by default, is formatted as a(n) ____, which cannot be moved to a precise location on a page.

Write a program that reads in the following data, all entered on one line with at least one space separating them: a) an integer

Rina8888 [55]

Answer:

import java.util.Scanner;

public class DataConstraint {

public static void main(String[] args) {

System.out.print("Enter month, day, year separated by spaces :");

Scanner sc=new Scanner(System.in);

int M,D,Y;

M=sc.nextInt();

D=sc.nextInt();

Y=sc.nextInt();

if(1<=M && M<=12 && 1<=D && D<=31 && Y>=1)

{

if(M==4 || M==6 ||M==9 || M==11){

if(D==31) {

System.out.println("month "+M+" can not have more than 30 days");

System.exit(0);

}

else if(M==2)

{

if((Y%400==0) || (Y%4==0 && Y%100!=0)) {

if(D>=30) {

System.out.println("month "+M+" cannot have "+D+" days");

System.exit(0);

}

else {

if(D>=29) {

System.out.println(Y+" is not a leap year, "+D+" is invalid");

System.exit(0);

}

System.out.println(M+" "+D+" "+Y+" is a valid date");

}

else{

if(1>=M || M>=12) System.out.println(M+" is not a valid month");

if(1>=D || D>=31) System.out.println(D+" is not a valid date");

if(Y<1) System.out.println("year can not be negative");

}

Explanation:

Use a conditional statement to check the month is between 1 and 12.
Check that the date is between 1 and 31 and year must be positive value.
If no. of days are more than 29, then the year cannot be a leap year.

4 0

3 years ago

You have been hired by an educational software company to create a program that automatically calculates the sum of each place-v

Vinvika [58]

Hi, you haven't provided the programing language, therefore, we will use python but you can extend it to any programing language by reading the code and the explanation.

Answer:

n1 = int(input("First numeber: "))

n2 = int(input("Second numeber: "))

for i in range(5):

r1 = n1%10

r2 = n2%10

print(r1+r2)

n1 = n1//10

n2 = n2//10

Explanation:

First, we ask for the user input n1 and n2
We create a for-loop to calculate the sum of each place-value of two numbers
We obtain the last number in n1 by using the mod operator (%) an the number ten this way we can always take the last value, we make the same for n2
Then we print the result of adding the last two numbers (place value)
Finally, we get rid of the last value and overwrite n1 and n2 to continue with the process

4 0

3 years ago

Write a program that takes paragraph from the user and prints all unique words in that paragraph using strings in c++

Bezzdna [24]

Answer:

void printUniquedWords(char filename[])

void printUniquedWords(char filename[]) {

void printUniquedWords(char filename[]) { // Whatever your t.text file is

fstream fs(filename);

fstream fs(filename); map<string, int> mp;

fstream fs(filename); map<string, int> mp; // This serves to keep a record of the words

string word;

string word; while (fs >> word)

string word; while (fs >> word) {

string word; while (fs >> word) { // Verifies if this is the first time the word appears hence "unique word"

if (!mp.count(word))

if (!mp.count(word)) mp.insert(make_pair(word, 1));

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++;

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; }

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close();

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close(); // Traverse map and print all words whose count

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close(); // Traverse map and print all words whose count //is 1

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close(); // Traverse map and print all words whose count //is 1 for (map<string, int> :: iterator p = mp.begin();

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close(); // Traverse map and print all words whose count //is 1 for (map<string, int> :: iterator p = mp.begin(); p != mp.end(); p++)

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close(); // Traverse map and print all words whose count //is 1 for (map<string, int> :: iterator p = mp.begin(); p != mp.end(); p++) {

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close(); // Traverse map and print all words whose count //is 1 for (map<string, int> :: iterator p = mp.begin(); p != mp.end(); p++) { if (p->second == 1)

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close(); // Traverse map and print all words whose count //is 1 for (map<string, int> :: iterator p = mp.begin(); p != mp.end(); p++) { if (p->second == 1) cout << p->first << endl;

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close(); // Traverse map and print all words whose count //is 1 for (map<string, int> :: iterator p = mp.begin(); p != mp.end(); p++) { if (p->second == 1) cout << p->first << endl; }

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close(); // Traverse map and print all words whose count //is 1 for (map<string, int> :: iterator p = mp.begin(); p != mp.end(); p++) { if (p->second == 1) cout << p->first << endl; } }

5 0

3 years ago

Which of the following behaviors does not harm a company if your employment is terminated?

saul85 [17]

Answer:

D. notifying your employer of all accounts you have access to, and requesting that they change all passwords before you leave

Explanation:

Assuming your employment is terminated, notifying your employer of all accounts you have access to, and requesting that they change all passwords before you leave is a behavior that would not harm a company. In the true and actual sense, making such suggestions is commendable because it would go a long way to cause more good rather than harm the company.

Some mischievous and malicious employees would rather not tell so they can still have an unauthorized access to the company's account and perpetrate various level of evil.

Hence, it is a good global practice to have a company's login credentials updated whenever an employee's employment is terminated.

3 0

3 years ago

Write a main function to do the following: Create a string that can hold up to 30 characters. Create an array of 10 strings with

masha68 [24]

Answer:

Check the explanation

Explanation:

#// do comment if any problem arises

//code

#include <stdio.h>

#include <ctype.h>

#include <string.h>

#include <stdlib.h>

void read(FILE *input, char array[10][61])

{

// read all 10 strings

for (int i = 0; i < 10; i++)

fgets(array[i], 60, input);

}

void remove_newline(char array[10][61])

{

for (int i = 0; i < 10; i++)

{

array[i][strlen(array[i]) - 1] = '\0';

}

void smallest(char array[10][61])

{

int s = 0;

for (int i = 1; i < 10; i++)

{

if (strlen(array[s]) > strlen(array[i]))

s = i;

}

printf("\nSmallest strnig: %s\n", array[s]);

}

void upper(char array[10][61])

{

for (int i = 0; i < 10; i++)

{

int n = strlen(array[i]);

for (int j = 0; j < n; j++)

{

array[i][j] = toupper(array[i][j]);

}

int main()

{

char filename[30];

// array of 10 strings

char array[10][61];

printf("Enter filename: ");

gets(filename);

// open file

FILE *input = fopen(filename, "r");

// read into array

read(input, array);

// close file

fclose(input);

// remove newline

remove_newline(array);

// print

printf("Contents of file:\n");

for (int i = 0; i < 10; i++)

printf("%s\n", array[i]);

// print smallest string

smallest(array);

// uppercase

upper(array);

// print again

printf("\nContents of file after converting to uppercase:\n");

for (int i = 0; i < 10; i++)

printf("%s\n", array[i]);

}

kindly check the attached image below to see the Output:

6 0

4 years ago