Answer:
D
Step-by-step explanation:
it's In the picture
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Answer:
this equation has exactly one solution ( unique )
![f(x)=2( \sqrt[3]{27})^{2x}](https://tex.z-dn.net/?f=f%28x%29%3D2%28%20%5Csqrt%5B3%5D%7B27%7D%29%5E%7B2x%7D%20)
Here 2 on left most side is the coefficient, 2x is the exponent and the of the function is cube root of 27.
So,
Thus, the simplified base for the function is 3. So correct answer is option B
2010 47 +ten thousand split decide and

restrict the domains of quadratic functions and absolute value functions, because these functions are

functions. For instance, the quadratic function f(x) = x^2 pairs both −2 and 2 with 4, and the absolute value function f(x) = |x| pairs both −2 and 2 with 2.
Linear functions (excluding constant functions) and exponential functions are

functions, so their domains

to be restricted.
_________________
An absolute value function, without domain restriction, has an inverse that is NOT a function.
In order to guarantee that the inverse must also be a function, we need to restrict the domain of the absolute value function to make it a one-to-one function.